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fenix001 [56]
1 year ago
13

How many minutes would be required to produce a mass of 6. 38 g al using a current of 12. 50 amps?

Chemistry
1 answer:
azamat1 year ago
5 0

To produce a mass of 6. 38 g al using a current of 12. 50 amps the time required would be 7207.4 minutes.

<h3>What is faraday law?</h3>

It states that the chemical which is getting decomposed because of the flow of current within an electrolyte is directly proportional to the quantity of electricity passing through it.

                        W= Z × I × t    Z = 1 coulomb

                                               I = current

                                                t = time

substituting the values

                           Z= 96500/Eq.wt

​Al 3+ +3e − →Al n= 3

so, Eq= 27 / 3 = 9

t = W × Z / I

t = 9 × 96500 / 12.50

t = 7207.4 minutes.

Therefore the time required would be, 7207.4 minutes.

Learn more about Faraday law, here:

brainly.com/question/1640558

#SPJ4

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Snezhnost [94]

Answer:

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Explanation:

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6 0
3 years ago
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If the energy difference between two electronic states is 214.68 kJ / mol , calculate the frequency of light emitted when an ele
atroni [7]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

Energy difference btween the two electronic states can be expressed as :

{ \qquad \sf  \dashrightarrow \: \Delta E = h\nu}

[ h = planks constant,{\: \nu }= frequency ]

\qquad \sf  \dashrightarrow \:214.68 = 39.79 \times 10 {}^{ - 14}  \times  \nu

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 \times 10 {}^{ - 4} }

\qquad \sf  \dashrightarrow \: \nu =  \cfrac{214.68}{39.79 }  \times 10 {}^{14}

\qquad \sf  \dashrightarrow \: \nu  \approx  5.395 \times10 {}^{14}  \:\:hertz

5 0
1 year ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
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Which answer is an isotope of 40/20x? <br><br> Question Pictured here:
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An isotope of ₂₀⁴⁰X  ⇒₂₀⁴⁴X

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms that have the same number of protons and a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

In the following element notation,

\large {{{A} \atop {Z}} \right X}

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  = number of protons + number of neutrons

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For symbol of isotope X :

₂₀X⁴⁰ : atomic number = 20, mass number = 40

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B. ₂₀⁴⁰X²⁺ : atomic number = 20, mass number = 40, neutrons=20

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D. ₂₀⁴⁴X : atomic number = 20, mass number = 44, neutrons=22

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<span>The superscripts in an electron configuration represents the number of electrons and protons in an element. </span>
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