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fenix001 [56]
1 year ago
13

How many minutes would be required to produce a mass of 6. 38 g al using a current of 12. 50 amps?

Chemistry
1 answer:
azamat1 year ago
5 0

To produce a mass of 6. 38 g al using a current of 12. 50 amps the time required would be 7207.4 minutes.

<h3>What is faraday law?</h3>

It states that the chemical which is getting decomposed because of the flow of current within an electrolyte is directly proportional to the quantity of electricity passing through it.

                        W= Z × I × t    Z = 1 coulomb

                                               I = current

                                                t = time

substituting the values

                           Z= 96500/Eq.wt

​Al 3+ +3e − →Al n= 3

so, Eq= 27 / 3 = 9

t = W × Z / I

t = 9 × 96500 / 12.50

t = 7207.4 minutes.

Therefore the time required would be, 7207.4 minutes.

Learn more about Faraday law, here:

brainly.com/question/1640558

#SPJ4

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What is the molar mass of an unknown gas<br> with a density of 4.95 g/L at 1.00 atm and<br> 25.0 °C?
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121 g/mol

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To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 1.00 atm                         R = 0.0821 L*atm/mol*K

V = 1.00 L                             T = 25.0. °C + 273.15 = 298.15 K

n = ? moles

PV = nRT

(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = n(0.0821 L*atm/mol*K)(298.15 K)

1.00 = (24.478115)n

0.0409 = n

Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.

0.0409 moles           ? grams           4.95 grams
----------------------  x  ------------------  =   ------------------
        1 L                       1 mole                     1 L

? g/mol = 121 g/mol

**note: I am not 100% confident on this answer

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