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Cerrena [4.2K]
3 years ago
8

Suppose you did the lab and someone came and said your unknown acid sample was

Chemistry
2 answers:
-BARSIC- [3]3 years ago
7 0

Answer:

I will love to help but I don't understand the question

s2008m [1.1K]3 years ago
7 0

Answer:

H2SO4

Explanation:

because it's not more acidic

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A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the
alexdok [17]

Answer : The volume of the bubble is, 625 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.4 atm

P_2 = final pressure of gas = 1.0 atm

V_1 = initial volume of gas = 250 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 15^oC=273+15=288K

T_2 = final temperature of gas = 27^oC=273+27=300K

Now put all the given values in the above equation, we get:

\frac{2.4atm\times 250mL}{288K}=\frac{1.0atm\times V_2}{300K}

V_2=625mL

Therefore, the volume of the bubble is, 625 mL

7 0
3 years ago
Copper(ii) chloride reacts with sodium nitrate to produce copper(ii) nitrate and sodium chloride.
zlopas [31]

Answer:

CuCl2 + 2NaNO3 - > Cu(NO3)2 + 2NaCl

5 0
2 years ago
What do chemists study
ANTONII [103]

Answer:

Chemists investigate the properties of matter at the level of atoms and molecules. They measure proportions and reaction rates in order to understand unfamiliar substances and how they behave, or to create new compounds for use in a variety of practical applications.

Explanation:

3 0
3 years ago
Read 2 more answers
How many moles of HCl are present in 0.70 L of a 0.63 M HCl solution?
eimsori [14]
So the molarity equation is moles of solute/liters of solution. so i’m pretty sure the answer should be 0.63/0.70= .9
7 0
3 years ago
You are given 3.0 grams of solid sodium to react to pure water which has a molarity of 55.6 M. How many milligrams of H2 can be
serious [3.7K]

Answer:

= 15.51 mL

Explanation:

Here's is the reaction:

2HgO(s) ⇒ 2 Hg(s)+O₂(g)

In this reaction 2mol HgO =  1mol O₂

The molecular weight of HgO = 216.59g

so, 3.0g HgO = 3.0g x 1.00molHgO/216.59gHgO

= 0.0138511 molHgO

The amount of Oxygen follows:

0.0138511 molHgOx1/2= 0.00692555 mol O₂

Now, volume of 1 any gas = 22400mL

so, 0.00692555 mol O₂ x22400mLO₂/1mol O₂

= 15.513232mL O₂

4 0
3 years ago
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