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2 years ago

Suppose you did the lab and someone came and said your unknown acid sample was

Chemistry

2 answers:

-BARSIC- [3]2 years ago

7 0

Answer:

I will love to help but I don't understand the question

s2008m [1.1K]2 years ago

7 0

Answer:

H2SO4

Explanation:

because it's not more acidic

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If a substance changes color, what has most likely happened

BabaBlast [244]

say for example, the color of our blood inside the body is blue, when you have a cut, th he blood color is red through oxygenation.

5 0

2 years ago

Which net ionic equation best represents the reaction that occurs when an aqueous solution of barium chloride is mixed with an a

vovangra [49]

Answer : The net ionic equation will be:

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

$BaCl_2(aq)+Li_2SO_4(aq)\rightarrow 2LiCl(aq)+BaSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow 2Li^+(aq)+2Cl^-(aq)+BaSO_4(s)$

In this equation the species, $Li^+\text{ and }Cl^{-}$ are the spectator ions.

By removing the spectator ions , we get the net ionic equation.

The net ionic equation will be:

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

6 0

2 years ago

Where are stars that are in their giant or super giant stages located on the Hertzsprung-Russell diagram?

maxonik [38]

I’m pretty sure it’s A) upper right!

3 0

3 years ago

The number of particles in 8 g 02 molecules are

igor_vitrenko [27]

Answer:

cholesterol

Explanation:

gsdhudbdjbfmcjfjdncbdhdnhdndbchdncbdn f f ff

5 0

2 years ago

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0

2 years ago