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garri49 [273]
2 years ago
12

Which of the following materials is the least porous?

Chemistry
2 answers:
stealth61 [152]2 years ago
8 0

Answer:

large pebbles and boulders

WARRIOR [948]2 years ago
3 0

Answer:

The answer is The unsorted sand and rock is the least porous.

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Question 1 (2 points)
allochka39001 [22]

The solution to the polynomial expression since the power of the variable is in the second degree is 6.29 × 10² cm

<h3>What is the power of a variable?</h3>

The power of a variable refers to the exponent of the variable and the highest power of a variable is the degree to which the variable is being raised. From the information given, the highest power of the variable is a polynomial.

Given that:

\mathbf{= 2.150  \times 10^2 \ cm + 7.34 \times 10^2 \ cm - 3.2 \times 10^2 \ cm }

So, since the exponents are in the same power we are going to add them all together multiplied by their exponent.

i.e.

\mathbf{= (2.150 + 7.34 - 3.2)   \times 10^2\ cm }

\mathbf{= 6.29 \times 10^2\ cm }

Learn more about the power of a variable here:

brainly.com/question/2495761

6 0
3 years ago
Answer all the following questions by putting a circle around a letter A.B.C or D
Nataly_w [17]

Answer:

C. 21%oxygen

Explanation:

Dry air contains 78.09% nitrogen, 20.95%oxygen, 0.93% argon, 0.04% carbon dioxide, and small amounts of other gases.

3 0
3 years ago
What does DNA instructions for making what
eduard

Answer:DNA contains the instructions needed for an organism to develop, survive and reproduce. To carry out these functions, DNA sequences must be converted into messages that can be used to produce proteins, which are the complex molecules that do most of the work in our bodies.

Explanation:

7 0
3 years ago
How many moles of solute particles are present in 1 ml of aqueous 0.020 m (nh4)2co3?
Dima020 [189]
Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?

For the purpose, here we will use the next equation:

c=n/V ⇒ n=cxV

n((NH4)2CO3) = 0.02M x 0.001L 

n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution


6 0
3 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
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