There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as
pH = pKa + log [A]/[HA]
where pKa = - log [Ka]
[A] is the concentration of the conjugate base
[HA] is the concentration of the acid
Given:
Ka = 1.8x10^-5
NaOH added = 0.015 mol
HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol
Solution:
pKa = - log ( 1.8x10^-5) = 4.74
[A] = 0.015 mol + 0.100 mol = .115 moles
[HA] = .1 - 0.015 = 0.085 moles
pH = 4.74 + log (.115/0.085)
pH = 4.87
The answer is A
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Answer:
77.14 atm of pressure should be of an acetylene in the tank.
Explanation:

According to reaction, 2 moles of acetylene reacts with 5 moles of oxygen.
Moles of oxygen=
Moles of acetylene =

Volume of large tank with oxygen gas, 
Pressure of the oxygen gas inside the tank = 
..[1]
Volume of small tank with acetylene gas ,
Pressure of the acetylene gas inside the tank = 
..[2]
Considering both the gases having same temperature T, [1]=[2]



77.14 atm of pressure should be of an acetylene in the tank.
Answer:
Density, D = 2g/cm^3
Explanation:
Given the following data;
Length = 2cm
Width = 3cm
Height = 2cm
Mass = 24g
Density = ?
Volume of a rectangular solid (V) = Length × Weight × Height
Therefore, V = L× W × H
Substituting the values, we have;
V = 12cm
Density can be defined as the ratio of mass to volume i.e mass all over volume.
Mathematically, 

Substituting the values, we have;

<em>Density, D = 2g/cm^3</em>
Hence, the density of the rectangular solid is 2g/cm^3.
I think it might be A or D, hope I helped! Sorry if I didn't!!