Explanation:
The given reaction is as follows.

Value of equilibrium constant is given as
= 4.3 \times 10^{6}[/tex].
Concentration of given species is
= 0.010 M;
= 10.M;
= 0.010 M.
Formula for experimental value of equilibrium constant (Q) is as follows.
Q =
Putting the given concentration as follows.
Q =
Q = 
Q = 
It is known that when Q >
, then reaction moves in the backward direction.
When Q <
, then reaction moves in the forward direction.
When Q =
, then reaction is at equilibrium.
As, for the given reaction Q >
then it means reaction moves in the backward direction.
Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.
<span>absorbed, radiated
Hope this helps. </span>
Given reactions:
(A) 6CO2(g) + 6H2O(l) + sunlight → C6H12O6(aq) + 6O2(g)
(B) 2H2(g) + O2(g) → 2H2O(g) + energy
Exothermic reactions are those which proceed with the release of heat/energy. In contrast, endothermic reactions proceed with the absorption of energy in the form of heat or light.
Since reaction A required sunlight, it is endothermic. Reaction B releases energy, hence exothermic
Ans: (B)
A is endothermic
B is exothermic
Explanation:
The given data is as follows.
(NaCl) = 
(H-O=C-ONO) = 
(HCl) = 
Conductivity of monobasic acid is 
Concentration = 0.01 
Therefore, molar conductivity (
) of monobasic acid is calculated as follows.

= 
= 
= 
Also,
= 
= 
= 
Relation between degree of dissociation and molar conductivity is as follows.

= 
= 0.1254
Whereas relation between acid dissociation constant and degree of dissociation is as follows.
K = 
Putting the values into the above formula we get the following.
K = 
= 
= 
= 
Hence, the acid dissociation constant is
.
Also, relation between
and
is as follows.

= 
= 3.7454
Therefore, value of
is 3.7454.