Answer:
Cu(s) + N₂(g) + 2O₂(g) ⟶ Cu(NO₂)₂(s)
Answer:
By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.
Half-life: 5,730 ± 40 years
Names: carbon-14, C-14, radiocarbon
Isotope mass: 14.003241 u
Answer:
15.5 moles
Explanation:
Applying,
PV = nRT.................. Equation 1
Where P = pressure, V = Volume, n = number of mole, R = molar gas constant, T = Temperature.
Make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 0.899 atm, V = 425 L, T = 24 °C = (273+24) K = 297 K.
Constant: R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.899×425)/(297×0.083)
n = 15.5 moles
Answer:
The runner should run 51 minutes.
Explanation:
Distance wished by runner to cover = d = 10.4 km
Time taken by the runner to cover 10.4 km = T
Speed of the runner = 7.6 mile/hour
1 mile = 1.60934 km
1 hour = 60 min
The runner should run 51 minutes.
Answer: all I know it’s not -31.5 for ppl taking the k12 test
Explanation: I took the test
