1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
boyakko [2]
2 years ago
6

What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?

Chemistry
2 answers:
____ [38]2 years ago
5 0

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

Ahat [919]2 years ago
5 0

The standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells is,

EθCell=+2.115lV

Cathode Mg2+/Mg

Anode Ni2+/Ni

What is a galvanic cell ?

  • A galvanic cell or voltaic cell is an electrochemical device that transforms the chemical energy of spontaneous redox reactions into electrical energy.
  • electrical cell A voltaic cell is an electrochemical device that produces electricity through chemical processes.
  • Use a table of standard electrode potential, such as this one from Chemistry LibreTexts, to look up the reduction potential for each of the questioned cells.

Mg2+(aq)+2le−→Mg(s)−Eθ=−2.372lV

Ni2+(aq)+2le−→Ni(s)−Eθ=−0.257lV

A galvanic cell's standard cell potential is equal to the cathode's standard reduction potential less the anode's standard reduction potential. Which is:

Eθcell=Eθ(Cathode)−Eθ(Anode)

=−0.257−(−2.372)

=+2.115

The standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells is,

EθCell=+2.115lV

Cathode Mg2+/Mg

Anode Ni2+/Ni

Learn more about Galvanic cell here:

brainly.com/question/23542257

#SPJ4

You might be interested in
I have no idea how to do this help plz!
Wittaler [7]
The answes are
C)
Then it is
)A
Im doing this for class too bruh
8 0
2 years ago
Read 2 more answers
determine the volume of your 0.25 m stock solution that is needed to make 200 ml of 0.010 m nacl. show all calculations
rusak2 [61]

The volume of your 0.25 m stock solution that is needed to make 200 ml of 0.010 m NaCl is <u>0.008 L</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

Calculation:-

C₁ =  0.25 M

V₁ = ?

C₂ = 0.010 M

V₂ = 200 ml = 0.2 L

V₁ = C₂V₂/C₁

    = 0.010 ×  0.2 /  0.25

   =<u> 0.008 L</u>

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

#SPJ4

5 0
9 months ago
How would this change affect the food web?check all that apply
klio [65]

During the summer, when the land is brown and the grass is green, the population of mice decreases because mice are easily spotted by the organisms that eat them.

How would this change affect the food web? Check all that apply.

A. It will increase the grass population.

D. It will decrease the snake population

E. It will increase the grasshopper population

hope this helps! If so please mark brainliest and rate/heart to help my account if it did!!

7 0
3 years ago
A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

5 0
3 years ago
Why is an excited atom more reactive than a neutral?
tester [92]
The excited atom is positive when then neutral has no charge

7 0
2 years ago
Other questions:
  • How many moles are in 2.0 grams of FeO
    14·2 answers
  • E85 fuel is a mixture of 85% ethanol and 15% gasoline by volume. What mass in kilograms of E85 (d = 0.758 g/mL) can be contained
    7·2 answers
  • The state of matter of a material depends on its what?
    13·2 answers
  • What is this: changing state from liquid to gas; gas bubbles form in the liquid
    11·1 answer
  • Which of the following bonds is most popular?<br> C-C,C-N,C-O,C-H
    10·1 answer
  • What is the chemica composition if the sun
    6·2 answers
  • According to the principle of the conservation of mass the mass of the sodium sulfate was the following PLS HELP I NEED TO TURN
    8·1 answer
  • a car is traveling at a speed of 55 mph the speed increased to 75 mph if the time needed to hange its speed is 4 seconds whats t
    12·1 answer
  • 2. In Experiment SOL, you investigated the solubility of oxalic acid. Sodium oxalate, Na2C2O¬4, is the sodium salt of this acid.
    9·1 answer
  • Helpppppppppppppppppppppppppppppppppppppppp
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!