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Annette [7]
2 years ago
14

2Al(s)+Fe2O3(s) → Al2O(s)+2Fe(s) with a delta H=-847 KJ.

Chemistry
1 answer:
Scrat [10]2 years ago
5 0

∆H for given reaction -847kJ

  • As it's negative reaction is exothermic

So

2 mol of Al releases 847KJ heat

4 mol Al releases

  • 2(847)
  • 1694KJ

∆H=-1694KJ

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