In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6*
(atoms of C in one mole) = 6.84* atoms.
2Al(s)+Fe2O3(s) → Al2O(s)+2Fe(s) with a delta H=-847 KJ.
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