Answer:
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Explanation:
Let x be the volume of fluid removed and the volume of pure antifreeze that is added. The concentration of antifreeze in the fluid is 0.3, the concentration in pure antifreeze is 1 and that in the final solution is 0.4 The volume of the final solution is 10.
(10 - x)(0.3) + x = 10(0.4)
0.3 + 0.7x = 0.4
x = 1/7 quarts
The volume that should be drained is 1/7 quarts
First take all percents and make them grams. Since you're not given a overall molar mass you can assume it is 100 and therefore the percents are their masses.
So you have 14.31g Carbon, 1.2g Hydrogen, and 84.49g of Chlorine. Next you divide each by their molar masses to get moles of each.
Carbon= <u>14.31</u>g Hydrogen= <u>1.2</u>g Chlorine= <u>85.49</u>g
12.01g 1.01g 35.45g
= 1.19moles = 1.188moles = 2.411moles
Next you divide each of those numbers by the smallest, in this case, Hydrogen.
Thus,
Carbon= <u>1.19moles</u> Hydrogen= <u>1.188moles</u> Chlorine= <u>2.411moles</u>
1.188moles 1.188moles 1.188moles
=1.002 =1 =2.02
These are all close enough to round, so your final empirical formula is: CHCl2
Hope that helps!!
