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ArbitrLikvidat [17]
3 years ago
15

Which skill involves creating representations of complex objects or processes? A. classifying B. predicting C. making models D.

evaluating (this is probably really easy, but my mind is going blank)
Chemistry
1 answer:
Murljashka [212]3 years ago
8 0

Answer:

C. making models

Explanation:

Making models facilitates constructing depictions of complex objects or practices that enable students to practice and understand how things work which can not be observed and measured directly. Model making needs abstract thinking about the tools and material used, spatial thinking, and well-organized idea of the project to create complex objects.

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A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t
drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t} (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>  

(a) We can calculate the energy (ΔU) using equation (1):

\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J  

(b) The work is related to pressure and volume by:

\Delta W = -p \Delta V

<em>where p: pressure and ΔV: change in volume = V final - V initial      </em>

\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J

(c) By the definition of Energy, we can calculate q:

\Delta U = \Delta W + \Delta q

<em>where Δq: is the heat transfer </em>

\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J    

I hope it helps you!  

6 0
3 years ago
Write an ionic equation for the reaction of acetic acid with sodium ethoxide, and specify whether the equilibrium favors startin
Elina [12.6K]
<h2>Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide</h2>

Explanation:

An ionic equation for the reaction of acetic acid with sodium ethoxide is as follows -

  • Reactants -

       Acetic Acid and Sodium ethanolate (sodium ethoxide)

  • Products -

       Butyric Acid and Sodium hydroxide

Hence,

     Acetic Acid + Sodium ethoxide ⇄ Butyric Acid + Sodium Hydroxide

     CH_3COOH + C_2H_5ONa ⇄ CH_3COOC_2H_5 + NaOH

  • Weak acids and bases have low energy than strong acids and bases.
  • The chemical equilibria shift the reaction side with the species having lower energy.
  • Given reaction is an acid-base reaction in which the equilibrium favors the starting material that means it will go to the side of the weakest acid that is acetic acid is weaker than butyric acid.
6 0
3 years ago
What tool(s) does God give us to help us in our everyday lives? PLZ HURRY!!!!!!!!!!!!!
romanna [79]

Answer:

Life

Explanation:

With out him we wouldn't live

5 0
4 years ago
Copper has a density of 8.96 g/cm3. If 75.0 g of copper is added to 50.0 mL of water in a graduated cylinder, to what volume rea
Tcecarenko [31]

Answer:

The answer to your question is    Final volume = 58.37 ml

Explanation:

Data

density = 8.96 g/cm³

mass = 75 g

volume of water = 50 ml

Process

1.- Calculate the volume of copper

  Density = mass / volume

Solve for volume

  Volume = mass / density

Substitution

  Volume = 75/8.96

Simplification

  Volume = 8.37cm³    or 8.37 cm³

2.- Calculate the new volume of water in the graduated cylinder

  Final volume = 50 + 8.37

  Final volume = 58.37 ml

3 0
3 years ago
calculate the mols of alt gas if the volume is 0.97 liters at a temperature of 12 C and the pressure is 152 Kpa’s
katrin2010 [14]

Answer:

0.062mol

Explanation:

Using ideal gas law as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821Latm/molK)

T = temperature (K)

Based on the information provided;

P = 152 Kpa = 152/101 = 1.50atm

V = 0.97L

n = ?

T = 12°C = 12 + 273 = 285K

Using PV = nRT

n = PV/RT

n = (1.5 × 0.97) ÷ (0.0821 × 285)

n = 1.455 ÷ 23.39

n = 0.062mol

4 0
3 years ago
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