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irga5000 [103]
3 years ago
12

Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.59×10−3.

Chemistry
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

E° = -0.133 V

Explanation:

In the reaction:

X(s) + Y⁺(aq) → X⁺(aq) + Y(s)

<em>1 electron is transferred from X to Y</em>

Now, using Nernst equation:

E° = RT / nF ln K

<em>Where R is gas constant (8.314 J/molK), T is absolute temperature (Usually 298.15K), n are transferred electrons (1, for the reaction), F is faraday constant (96485C/mol) and K is equilibrium constant (5.59x10⁻³)</em>

Replacing:

E° = 8.314 J/molK*298.15K / 96485C/mol*1 ln 5.59x10⁻³

<em>E° = -0.133 V</em>

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2 years ago
A sealed 1.0 L flask is charged with 0.500 mol of I2 and 0.500 mol of Br2. An equilibrium reaction ensues: I2 (g) + Br2 (g) ↔ 2I
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Answer:  Thus the value of K_{eq} is 110.25

Explanation:

Initial moles of  I_2 = 0.500 mole

Initial moles of  Br_2 = 0.500 mole

Volume of container = 1 L

Initial concentration of I_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M

Initial concentration of Br_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M

equilibrium concentration of IBr=\frac{moles}{volume}=\frac{0.84mole}{1L}=0.84M [/tex]

The given balanced equilibrium reaction is,

                            I_2(g)+Br_2(g)\rightleftharpoons 2IBr(g)

Initial conc.              0.500 M     0.500 M             0  M

At eqm. conc.    (0.500-x) M      (0.500-x) M     (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}

K_c=\frac{(2x)^2}{(0.500-x)\times (0.500-x)}

we are given : 2x = 0.84 M

x= 0.42

Now put all the given values in this expression, we get :

K_c=\frac{(0.84)^2}{(0.500-0.42)\times (0.500-0.42)}

K_c=110.25

Thus the value of the equilibrium constant is 110.25

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