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irga5000 [103]
3 years ago
12

Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.59×10−3.

Chemistry
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

E° = -0.133 V

Explanation:

In the reaction:

X(s) + Y⁺(aq) → X⁺(aq) + Y(s)

<em>1 electron is transferred from X to Y</em>

Now, using Nernst equation:

E° = RT / nF ln K

<em>Where R is gas constant (8.314 J/molK), T is absolute temperature (Usually 298.15K), n are transferred electrons (1, for the reaction), F is faraday constant (96485C/mol) and K is equilibrium constant (5.59x10⁻³)</em>

Replacing:

E° = 8.314 J/molK*298.15K / 96485C/mol*1 ln 5.59x10⁻³

<em>E° = -0.133 V</em>

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3 years ago
it takes 463 kJ/mol to break an oxygen-hydrogen single bond. calculate the maximum wavelength of light for which an oxygen-hydro
Marianna [84]

Answer:

  • <u>2.59 × 10⁻⁷ m  = 259 nm</u>

Explanation:

You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.

The energy of a photon and its wavelength are related by the Planck - Einstein equation:

  • E = hν,

Where:

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  • h = Planck constant (6.626 × 10⁻³⁴ J . s) and
  • ν = frequency of the photon.

And:

  • ν = c / λ

Where:

  • c = speed of light (3.00 × 10⁸ m/s in vacuum)
  • λ = wavelength of the photon

Thus, you can derive:

  • E = h c / λ

Solve for λ:

  • λ = h c / E

Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond

  • 463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom

       = 7.69×10²³ J / bond

Substitute the values and use the energy of one bond:

  • λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m

The wavelength of light is usually shown in nanometers:

  • 2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer
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6.022 x 10^23)  x0.041=2.469 x10^22molecules
3 0
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