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Inga [223]
2 years ago
6

Calculate the total binding energy, and the binding energy per nucleon, for 73Li37Li . The masses of the atoms of 73Li37Li and 1

1H11H are 7.016004 uu and 1.007825 uu , respectively. The mass of a neutron is 1.008665 uu . Express your answe
Chemistry
1 answer:
frosja888 [35]2 years ago
8 0

The total binding energy for lithium is 39.25 Mev

The binding energy per nucleon for lithium is 5.61 Mev / nucleon

<h3>BINDING ENERGY</h3>

    Binding energy is the total energy required for the breakdown of a nucleus to its component nucleons

<h3>TOTAL BINDING ENERGY</h3>

    Total binding energy is the amount of energy released when the atom is formed from its constituent electron, protons and neutrons.

The given mass are lithium is 7.016004 u  and hydrogen is 1.007825

There are 3 hydrogen and 4 neutrons

To calculate the Total binding energy

3 ( 1.0782) +  4 ( 1.008665 ) = 7.058135 u

Mass of neutron is 1.008665 u

1 atomic mass unit is 931.5 Mev

<h3>The total binding energy is</h3>

TBe = ( 7.058135 - 7.016004 ) × 931.5

       = 39.25 Mev

Total binding energy is 39.25 Mev

<h3>To calculate the binding energy</h3>

BE= 39.25 / 7

    = 5.61 Mev / neucleon

Hence, The total binding energy is 39.25 Mev.

             The binding energy is 5.61 Mev / neucleon.

Learn more about the binding energy on

brainly.com/question/4334375

#SPJ4

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