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Vladimir79 [104]
2 years ago
12

When δh for a thermochemical equation is negative, that reaction is _____, while a positive value for δh is associated with an

_____ reaction.
Chemistry
1 answer:
denis-greek [22]2 years ago
6 0

When Δh for a thermochemical equation is negative, that reaction is Exothermic while a positive value for Δh is associated with an endothermic reaction.

Thermochemical Equation is a balanced stoichiometric chemical equation that includes the enthalpy change, ΔH.Thermochemical Equation is a balanced stoichiometric chemical equation that encompass the enthalpy fee ΔH.In variable shape a thermochemical Equation like this . A+B→CΔH=x KJ/mol.

An exothermic system releases warmth, inflicting the temperature of the immediate surroundings to upward thrust. An endothermic manner absorbs warmness and cools the environment.

An endothermic system is in which warmness is transferred from the environment to the systems. So the device has won warmness from the surroundings. The alternate in enthalpy, delta H is fantastic for an endothermic technique. An instance could be melting an ice cube.

Learn more about exothermic reaction here:-brainly.com/question/2924714

#SPJ4

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What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according
ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

<u>Step 1: </u>The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

<u>Step 2: </u>Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

<u>Step 3: </u>Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

<u>Step 4: </u>Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M  = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0
3 years ago
Percent Error Problems – Find the percent error for each problem below.
Citrus2011 [14]

% error = 3.4 %

Percent error = |accepted value - experimental value|/accepted value × 100%

∴ % error = |355 mL – 343 mL|/355 mL × 100 % = |12|/355 × 100 % = 3.4 %

5 0
3 years ago
Consider the reaction. 2c(s,graphite) h2= c2h2(g) Based on the equation and the information in the table, what is the enthalpy o
xxTIMURxx [149]
<h3>The enthalpy of the reaction : C.226.73 kJ</h3><h3>Further explanation</h3>

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The change in enthalpy in the formation of 1 mole of the elements is called enthalpy of formation

Delta H reaction (ΔH) is the difference between product enthalpy and reactant enthalpy (Hp-Hr)

Reaction :

2C + H2 -> C2H2

(ΔH) reaction = (ΔH) product - (ΔH) reactants

(ΔH) reaction = (ΔH) C2H2 - ((ΔH) C + (ΔH) H2)

for free element (ΔH) it has zero value, so (ΔH) C and (ΔH) H2 have zero value

From the available data: Hf (kJ / mol) C2 H2 (g)=  226.73

then

(ΔH) reaction = ΔH) C2H2 - ((ΔH) C + (ΔH) H2)

(ΔH) reaction = 226.73 - (0 + 0)

(ΔH) reaction = 226.73 (answer C)

<h3>Learn more</h3>

(ΔH) reaction

brainly.com/question/1889660

Keywords : (ΔH) reaction, C2H2

8 0
3 years ago
Read 2 more answers
A pure gold ring weighs 23.5 grams. How many atoms of gold<br> are in the ring?
Digiron [165]

The number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

<h3>HOW TO CALCULATE NUMBER OF ATOMS?</h3>

The number of atoms in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.

The number of moles in the gold (Au) can be calculated by dividing the mass of gold by its molar mass (196.97g/mol).

no. of moles = 23.5g ÷ 196.97g/mol

no. of moles = 0.119mol

Number of atoms in Au = 0.119 × 6.02 × 10²³

no. of atoms = 7.18 × 10²² atoms.

Therefore, the number of atoms of gold in the pure ring are 7.18 × 10²² atoms.

Learn more about number of atoms at: brainly.com/question/15959704

3 0
3 years ago
Using current genetic engineering techniques can provide potential benefits for parents, including
Black_prince [1.1K]

Answer:

conceiving a child who is a bone marrow match to a living child.

Explanation:

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3 years ago
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