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Andrews [41]
1 year ago
8

What is the oxidation number of boron in Na(B(NO3)4)

Chemistry
2 answers:
Vitek1552 [10]1 year ago
7 0

Answer:

the oxidation state od boron in sodium boron hydride is (+3).

aleksklad [387]1 year ago
3 0

Answer:

+3

Explanation:

oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as hydride. thus the oxidation state od boron in sodium boron hydride is (+3)

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Mr. Aguilar has ice on his wrist, literally. If the ice on Mr. Aguilar’s wrist (H2O) weighs 546 grams, how many ice particles ar
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The answer to your question is  1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

                   = 2 + 16

                   = 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

                 18 g ---------------- 6.023 x 10²³ particles

                546 g ---------------   x

                  x = (546 x 6.023 x 10²³) / 18

3.- Simplification

                  x = 3.289 x 10²⁶ / 18

4.- Result

                  x = 1.83 x 10²⁵ particles

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