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Andrews [41]
1 year ago
8

What is the oxidation number of boron in Na(B(NO3)4)

Chemistry
2 answers:
Vitek1552 [10]1 year ago
7 0

Answer:

the oxidation state od boron in sodium boron hydride is (+3).

aleksklad [387]1 year ago
3 0

Answer:

+3

Explanation:

oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as hydride. thus the oxidation state od boron in sodium boron hydride is (+3)

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