What is the oxidation number of boron in Na(B(NO3)4)
2 answers:
Answer:
the oxidation state od boron in sodium boron hydride is (+3).
Answer:
+3
Explanation:
oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as hydride. thus the oxidation state od boron in sodium boron hydride is (+3)
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