Answer: The mass of deposited cadmium is 23.9g
Explanation:
According to Faraday Law of Electrolysis, the mass of substance deposited at the electrode is directly proportional to the quantity of electricity passed through the electrolyte.
Faraday has found that the amount of electricity needed to liberate one gm eq. of substance from an electrolyte is 96500C.
Given that
time (t) =1.55min *60 =93seconds
Current (I) =221A
Q= It = 221 * 93 =20553C
Molar mass of CdS04 =112.41
96500C will liberate 112.41g
20553C will liberate Xg
Xg= (20553*112.41)/96500
=23.9g
Therefore , the amount of Cd deposited at the electrode is 23.9g
The purpose of this process is to make sure that the substance is completely melted before trying to figure up the mass. if there are still bits of solid in the liquid the mass will be incorrect if just taken the first time. Also, some substances have gaseous elements in them so to heat it up, it releases those gases and you’re left with the true mass in the liquid.
hope this helps!
Answer:
When mixed with a solution of aqueous sodium carbonate, a solution containing copper (II) ions will form a precipitate.
Explanation:
A precipitation reaction is a reaction in which one of the products is insoluble in the solvent of the reaction (this is usually water).
These reactions are one of the types of double-displacement reactions in which the cations and anions of the reactants are inter-changed.
When mixed with a solution of aqueous sodium carbonate, a solution containing copper (II) ions will form a precipitate which is insoluble in water.
The copper (II) ions will form together with the carbonate, a precipitate. Which will be insoluble. An example is CuSO4.
Na2CO3 + CuSO4 → 2Na+ + CO32- + Cu+ + SO42- →2Na+ + SO42- + CUCO3
D is incorrect it is not a compound.