A sample of fluorine gas exerts a pressure of 900 mmHg. When the pressure is changed to 1140 mmHg, the volume is 250 mL. What wa
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Answer:
ΔP = -3556.36 Pa
Explanation:
Atmospheric pressure, P = 101300 Pa
Latent heat of boiling water,
Boiling point at atmospheric pressure, T = 373.15 K
ΔT = 1 K
The change in volume as the water boils to vapor will be
Since the volume of vapor () is far greater than the volume of liquid (
)
Using the ideal gas equation:
R = 8.314 J/mol-K
ΔV = 0.0306 m³
Molecular weight of water, MW = 0.018 kg/mol
Using the Clausius - Clapeyron equation:
ΔP = -3556.36 Pa
But the pressure change is said to lower the boiling point of water, only a negative pressure change will lower the boiling point.
ΔP = 3556.36 Pa
Answer:
The new volume of the balloon be .
Explanation:
We have,
Initial volume is 556 cm ³
The temperature of the balloon decreases from 278 K to 231 K.
We need to find the new volume of the balloon if the pressure is constant.
The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.
, P is constant
So, the new volume of the balloon be .