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charle [14.2K]
2 years ago
6

Perform the following

Chemistry
1 answer:
strojnjashka [21]2 years ago
7 0

Answer:

4 sig figs: 20.18

Explanation:

the smallest amount of digits was 4 in the expression

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Compare the potential energy of two atoms chemically bonded to their potential energy when separated.
ikadub [295]

Answer:

See explanation

Explanation:

The essence of chemical bonding is in order to attain minimum energy. The minimum energy state is the most stable state of a chemical system.

As the distance of separation between atoms decreases, the potential energy of the system decreases accordingly.

An optimum distance is reached when the two atoms attain the lowest potential energy. This is designated as the bond distance of the two atoms.

Hence two atoms have lower potential energy when bonded than when separated at large distance.

6 0
3 years ago
Who conducted experiments to determine the quantity of charge
____ [38]

J. J. Thomson is the corect awncer

5 0
2 years ago
How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?
nevsk [136]

Answer:

17.5 g

Explanation:

Given data

  • Mass of solution to be prepared: 50.0 grams
  • Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl

4 0
3 years ago
When a radioactive sample decays for 2 half-lives the amount remaining will be ____ of the original?
mash [69]
1/4 of the original.
4 0
3 years ago
G. whose vapour
german

Answer:

8.33 hours

Explanation:

In order to solve this problem, we must apply Graham's law of diffusion in gases. Graham's law states that the rate of diffusion of a gas is inversely proportional to the square root of its vapour density. For two gases we can write;

R1/R2=√d2/d1

Where;

R1= rate of diffusion of hydrogen

R2= rate diffusion of unknown gas

d1= vapour density of hydrogen

d2= vapour density of the unknown gas

Volume of hydrogen gas = 360cm^3

Time taken for hydrogen gas to diffuse= 1 hour =3600 secs

R1 = 360 cm^3/3600 secs = 0.1 cm^3 s-1

Vapour density of unknown gas = 25

Vapour density of hydrogen = 1

Substituting values,

0.1/R2 = √25/1

0.1/R2 = 5/1

5R2 = 0.1 × 1

R2 = 0.1/5

R2= 0.02 cm^3s-1

Volume of unknown gas = 600cm^3

Time taken for unknown gas to diffuse= volume of unknown gas/ rate of diffusion of unknown gas

Time taken for unknown gas to diffuse= 600/0.02

Time= 30,000 seconds or 8.33 hours

8 0
2 years ago
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