Answer : The volume of one mole of gas is dependent of temperature and pressure.
Explanation:
At <span><span>0o</span>Cand1atm</span> one mole of an ideal gas would be <span>≈22.4L</span>, which is the same as <span>22.4d<span>m3</span></span>
If you double the pressure, the same amount (mole) of gas would take up only half the space.
If the temperature changes (and pressure stays constant), the gas will expand or contract by about <span>1%/<span>3o</span></span>.
Answer:
w = vR/3
Explanation:
The centre of mass of the loop to bullet system is given by D / 4 from centre of loop, which is equivalent to R / 2 from its centre.
From the principle of conservation of linear momentum
, we have
m*v = 2*m* Vcm
Where v = velocity of bullet, Vcm = velocity of wood
Hence, we have
Vcm = v2
Also, from the conservation of angular momentum about the centre of mass.
M*V*(R/2) = Ic*w - equation (I)
where Ic = moment of inertia and w = angular velocity
Ic for a ring is given by
Ic of a bullet is given by
Hence, the moment of inertia of the system is given by the summation of the two moments of inertia Ic(ring) + Ic(bullet) which gives
Ic(system) = 
Substituting back into equation (I), we have

Hence, we obtain w =vR/3
w=v3R
Ok so the first thing you need to do is im not gonna help you