Answer:
F₁ = F₂ = F₃ = 0 N
Explanation:
given,
Arrow 1 mass = 80 g   speed = 10 m/s
Arrow 2 mass = 80 g   speed = 9 m/s
Arrow 3 mass = 90 g   speed = 9 m/s
Horizontal Force:- F₁ , F₂ and F₃
There is no air resistance.
If Air resistance is zero then the horizontal acceleration of the arrow also equal to zero.
We know,
According to newton's second law
         F = m a
If Acceleration is equal to zero
Then Force is also equal to zero.
Hence, F₁ = F₂ = F₃ = 0 N
 
        
             
        
        
        
With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x  N and 66 degrees
 N and 66 degrees
ELECTRIC FORCE (F)
F = 
Where K = 9 x  N
 N /
/
The distance between  and
 and  can be calculated by using Pythagoras theorem.
 can be calculated by using Pythagoras theorem.
d = 
d = 46.7 cm = 0.467 m
For force  , substitute all the parameters into the formula above
, substitute all the parameters into the formula above
 = (9 x
 = (9 x  x 3 x 1)/
 x 3 x 1)/
 = 2.7 x
 = 2.7 x  /0.218
/0.218
 = 1.24 x
 = 1.24 x  N
 N
For force  , substitute all the parameters into the formula above
, substitute all the parameters into the formula above
 = (9 x
 = (9 x  x 3 x 4)/
 x 3 x 4)/
 = 1.08 x
 = 1.08 x  /0.1089
/0.1089
 = 9.92 x
 = 9.92 x  N
 N
For force  , substitute all the parameters into the formula above
, substitute all the parameters into the formula above
 = (9 x
 = (9 x  x 3 x 2)/
 x 3 x 2)/
 = 5.4 x
 = 5.4 x  /0.1089
/0.1089
 = 4.96 x
 = 4.96 x  N
 N
Summation of forces on Y component will be
 =
 =  -
 -  Sin 45
 Sin 45
 = 9.92 x
 = 9.92 x  - 1.24 x
 - 1.24 x  Sin 45
 Sin 45
 = 9.04 x
 = 9.04 x  N
 N
Summation of forces on X component will be
 =
 =  -
 -  Cos 45
 Cos 45
 = 4.96 x
 = 4.96 x  - 1.24 x
 - 1.24 x  Sin 45
 Sin 45
 = 4.08 x
 = 4.08 x  N
 N
Net Force = 
Net force = 
Net force = 9.9 x  N
 N
The direction will be 
Tan ∅ =  /
/
Tan ∅ = 9.04 x  / 4.08 x
 / 4.08 x 
Tan ∅ = 2.216
∅ =  (2.216)
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x  N and 66 degrees approximately.
 N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
 
        
                    
             
        
        
        
Answer:
4.4×10⁻⁷ Coulomb
Explanation:
V = Voltage = 5.8 kV
d = Potential distance = 2.8 mm = 0.0028 m
A = Area = 0.3×0.08 = 0.024 m²
ε₀ = permittivity constant in a Vacuum= 8.85×10⁻¹² F/m

Magnitude of charge transferred between a carpet and a shoe is 4.4×10⁻⁷ Coulomb.
 
        
             
        
        
        
The degree is 4678% to pass theough all membranes.
        
             
        
        
        
Answer:
<u><em>Circular motion requires a net inward or "centripetal" force. Without a net centripetal force, an object cannot travel in circular motion. In fact, if the forces are balanced, then an object in motion continues in motion in a straight line at constant speed.</em></u>
Explanation: