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kirza4 [7]
3 years ago
6

An ore sample is found to contain 10.500000 g of cobalt and 87.3 g waste rock (gangue). What is the

Chemistry
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

\% Co=10.7\%

Explanation:

Hello!

In this case, since this is a mixture composed by cobalt and waste rock, we can compute the percent by mass of cobalt as shown below:

\% Co=\frac{m_{Co}}{m_{Co}+m_{waste}} *100\%\\\\

Thus, we plug in to obtain:

\% Co=\frac{10.500000g}{10.500000g+87.3} *100\%\\\\\% Co=10.7\%

Best regards!

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Convert 614 Cal to J. Only include the numerical value in your answer. Respond with the correct number of significant figures in
Kruka [31]

Answer:

Explanation:

Given parameters:

Number of given calories = 614 cal

Note that  1cal = 4.18J

Now to convert the given calories to joule, we use the relationship below:

         Since 1Cal gives 4.18Joule of energy

                614Cal will produce 4.18 x 614;

                   2566.52J of energy.

This written as 2.57 x 10³J because it has three significant numbers of 2, 5 and 7.

In writing an operation that involves deducing the significant numbers, we simply express our answer to that shows the lowest number of significant numbers. Our problem has 3 significant numbers each and the answer is given in that regard.

7 0
3 years ago
1. A container holds four times as many moles of CO2 as O2. If the total pressure in the container is 20. atm,
Hitman42 [59]

Answer:

Partial pressure of CO2 = 16 atm

Explanation:

Total number of moles of gases = 4+1 = 5 moles

Mole fraction of CO2 = 4/5

Partial pressure of CO2 = mole fraction of CO2 × total pressure

Partial pressure of CO2 = (4/5) × 20

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7 0
3 years ago
What type(s) of orbital overlap is(are) used to form the indicated bond in the following structure.
lorasvet [3.4K]
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3 0
2 years ago
Why do you move the .0100 - x to the left side of the equal sign?
dlinn [17]
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5 0
3 years ago
A rectangular prism of volume 84 cm 3 has a mass of 760 g. What is the density of the rectangular prism? 5.8 g•cm 3 9.0 g/cm 3 6
Fiesta28 [93]

Answer:

9.0 g/cm³

Explanation:

Density can be computed with the formula:

D=\dfrac{M}{V}

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D = Density

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84 cm³ = volume

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So we just plug in our given into the formula:

D=\dfrac{M}{V}

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3 years ago
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