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kirza4 [7]
3 years ago
6

An ore sample is found to contain 10.500000 g of cobalt and 87.3 g waste rock (gangue). What is the

Chemistry
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

\% Co=10.7\%

Explanation:

Hello!

In this case, since this is a mixture composed by cobalt and waste rock, we can compute the percent by mass of cobalt as shown below:

\% Co=\frac{m_{Co}}{m_{Co}+m_{waste}} *100\%\\\\

Thus, we plug in to obtain:

\% Co=\frac{10.500000g}{10.500000g+87.3} *100\%\\\\\% Co=10.7\%

Best regards!

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solong [7]

The molar Concentration of KMnO₄ is 0.000219 M

Concentration is the abundance of a constituent divided by means of the overall extent of an aggregate. numerous styles of mathematical description may be outstanding: mass awareness, molar awareness, variety concentration, and quantity awareness.

y is absorbance

x is the molar concentration of KMnO_4

y = 4.84E + 03x - 2.26E - 01

0.833 = 4.84 * 10⁺⁰³ x - 2.26 * 10⁻¹

1.059 = 4.84 * 10⁺⁰³ x

X = 0.000219 M

Hence, The molar Concentration of KMnO₄ is 0.000219 M

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2 years ago
Which of the following is NOT an example of a Heterogeneous Mixture?
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Answer:

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3 years ago
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Una muestra de oxígeno ocupa 4.2 litros a 760 mm de hg . ¿ cual será el volumen del oxigeno a 415 mm de hg , si la temperatura p
ddd [48]

Teniendo en cuenta la ley de Boyle, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Al aumentar el volumen, las partículas (átomos o moléculas) del gas tardan más en llegar a las paredes del recipiente y por lo tanto chocan menos veces por unidad de tiempo contra ellas. Esto significa que la presión será menor porque ésta representa la frecuencia de choques del gas contra las paredes.

De esta manera se relaciona la presión y el volumen, determinando la ley de Boyle que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:

P×V=k

Teniendo un estado inicial 1 y final 2, se cumple:

P₁×V₁= P₂×V₂

En este caso, se sabe que:

  • P₁= 760 mmHg
  • V₁= 4.2 L
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Reemplazando en la expresión matemática para la Ley de Boyle:

760 mmHg× 4.2 L= 415 mmHg× V₂

Resolviendo:

(760 mmHg× 4.2 L)÷ 415 mmHg= V₂

<u><em>7,69 L= V₂</em></u>

Finalmente, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

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Elements in the same period have the same amount of atomic orbits.

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