Answer:

Explanation:
<u>Molecular formula from Glucose:</u>
C₆H₁₂O₆
<u>3 moles of Glucose:</u>
3C₆H₁₂O₆
In 1 mole of Glucose, there are 12 hydrogen atoms.
<u>In 3 moles:</u>
= 12 × 3
= 36 H atoms
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.
Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be
g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.
Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is
for
.
<h3>What is the enthalpy of reaction?</h3>
The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.
The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.
The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.
The combustion of octane can be given as:

Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is
. Thus, option B is correct.
Learn more about enthalpy of reaction, here:
brainly.com/question/1657608
Answer:
I think
1. A
2. 400
3. 100
4. IDK srry
Explanation:
Ijust want to help, but I also want brainliest