The force would be a balanced force because both of the people are using the same force so it would not move.
Answer:
The correct answer is 0.89 mol.
Explanation:
At STP (Standard Temperature and Pressure) conditions, 1 mol of an ideal gas occupies a volume of 22.4 L. If we assume STP conditions, we can consider a convertion factor of 1 mol/22.4 L to convert the volume of NO₂ from liters to moles:
20,00 L x 1 mol/22.4 L = 0.89 mol
So, at STP, we would have 0.89 mol of NO₂
Copper= 79.853%
Sulfide= 20.147%
Hope this helps.
Explanation:
Hey there!!
We generally use s,p,d,f formula.
So, let's do with it.
1.Neon
Atomic no. = 10
So, Its electronic configuration is;
![= 1 {s}^{2} .2 {s}^{2} 2 {p}^{6}](https://tex.z-dn.net/?f=%20%3D%201%20%20%7Bs%7D%5E%7B2%7D%20.2%20%7Bs%7D%5E%7B2%7D%202%20%7Bp%7D%5E%7B6%7D%20)
2.Zinc.
Atomic no. = 30
So, it's electronic configuration is;
![= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}](https://tex.z-dn.net/?f=%20%3D%201%20%7Bs%7D%5E%7B2%7D%202%20%7Bs%7D%5E%7B2%7D%202%20%7Bp%7D%5E%7B6%7D%203%20%7Bs%7D%5E%7B2%7D%203%20%7Bp%7D%5E%7B6%7D%204%20%7Bs%7D%5E%7B2%7D%203%20%7Bd%7D%5E%7B10%7D%20)
3. Tungsten.
Atomic no. = 74.
So, it's electronic configuration is;
![= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{10}4 {p}^{6} 5 {s}^{2} 4 {d}^{10} 5 {p}^{6} 6 {s}^{2} 4 {f}^{14} 5 {d}^{4}](https://tex.z-dn.net/?f=%20%3D%201%20%7Bs%7D%5E%7B2%7D%202%20%7Bs%7D%5E%7B2%7D%202%20%7Bp%7D%5E%7B6%7D%203%20%7Bs%7D%5E%7B2%7D%203%20%7Bp%7D%5E%7B6%7D%204%20%7Bs%7D%5E%7B2%7D%203%20%7Bd%7D%5E%7B10%7D4%20%7Bp%7D%5E%7B6%7D%205%20%7Bs%7D%5E%7B2%7D%204%20%7Bd%7D%5E%7B10%7D%205%20%7Bp%7D%5E%7B6%7D%206%20%7Bs%7D%5E%7B2%7D%204%20%7Bf%7D%5E%7B14%7D%205%20%7Bd%7D%5E%7B4%7D%20)
4. Magnesium.
Atomic no. = 12
So, the electronic configuration is ;
![= 1 {s}^{2} 2 {s}^{2} 2 {p}^{6}3 {s}^{2}](https://tex.z-dn.net/?f=%20%3D%201%20%7Bs%7D%5E%7B2%7D%202%20%7Bs%7D%5E%7B2%7D%202%20%7Bp%7D%5E%7B6%7D3%20%7Bs%7D%5E%7B2%7D%20%20)
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
hi umm I don't know what to say