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pychu [463]
3 years ago
15

How many particles of Na are there in 1.43g of a molecular compound with a Molar mass of 23g?

Chemistry
1 answer:
Olin [163]3 years ago
7 0

Answer:

3.74 x 10²² particles

Explanation:

Given parameters:

Mass of compound  = 1.43g

Molar mass of compound  = 23g

Unknown:

Number of particles of sodium = ?

Solution:

To find the number of particles of Na in the compound, we need to obtain the mass of sodium from the total mass given;

          Mass of sodium  = \frac{molar mass of Na}{molar mass of compound} x mass of sample

                                      = \frac{23}{23}  x 1.43g

                                       = 1.43g

Now find the number of moles of this amount of Na in the sample;

          Number of moles  = \frac{mass}{molar mass} = \frac{1.43}{23}  = 0.062mole

Now;

                    1 mole of substance  = 6.02 x 10²³ particles

                       0.062 mole of substance  =  0.062 x 6.02 x 10²³ particles

                                                                     = 3.74 x 10²² particles

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Answer: Thus ∆H, in kJ/mol, for the dissolution of MgSO₄ is -66.7 kJ

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