Question

A solution is prepared by dissolving 32. 0 g of NiSO4 in water. What current would be needed to deposit all of the nickel in 5. 0 hours?

Answer 1

The current needed to deposit all of the nickel in 5 hours is 2.219 A

What is Faraday's Law of electrolysis?

According to the first law of Faraday, the amount of substance liberated at an electrode is directly proportional to the quantity of charge passed through an electrolyte.

m = zq , where z = electrochemical equivalent

An electrochemical equivalent is the mass of the substance liberated at an electrode when 1 Columb of charge is passed through the electrolyte.

For the nickel,

$Ni^{2+} (aq) + 2e^- \rightarrow Ni (s)$

z = 2

The molar mass of NiS0₄ = 154.75 g

154.75 g of Ni needs 2 x 96485 C

32 g of Ni needs $\frac{2\times 96485\times 32}{154.75}$

32 g of Ni needs 39944.79 C

We know,

q = It

Where q = charge

I = current and t = time in seconds

q = 39944.79 C and t = 5 x 60 x 60 = 18000 s

$I = \frac{q}{t} \\ = \frac{39944.79}{18000}$

= 2.219 A

Hence, the current needed to deposit all the nickel is 2.219 A in 5 hours

Learn more about Faraday's law of electrolysis:

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