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uysha [10]
2 years ago
11

The pH of a saturated solution of a metal hydroxide MOH is 10.15. Calculate the Ksp for this compound.

Chemistry
1 answer:
Airida [17]2 years ago
4 0

Answer:

Ksp=2.00x10^{-8}

Explanation:

Hello!

In this case, since the pH of the given metal is 10.15, we can compute the pOH as shown below:

pOH=14-pH=14-10.15=3.85

Now, we compute the concentration of hydroxyl ions in solution:

[OH^-]=10^{-pOH}=10^{-3.95}=1.41x10^{-4}M

Now, since this hydroxide has the form MOH, we infer the concentration of OH- equals the concentration of M^+ at equilibrium, assuming the following ionization reaction:

MOH(s)\rightarrow M^+(aq)+OH^-(aq)

Whose equilibrium expression is:

Ksp=[M^+][OH^-]

Therefore, the Ksp for the saturated solution turns out:

Ksp=1.41x10^{-4}*1.41x10^{-4}\\\\Ksp=2.00x10^{-8}

Best regards!

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