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2 years ago

Write the henderson-hasselbalch equation for a propanoic acid solution (ch3ch2co2h, pa=4. 874)

Chemistry

1 answer:

Mariana [72]2 years ago

7 0

The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

<h3>What is Henderson Hasselbalch Equation ?</h3>

It is expressed as:

pH = pKa + log([A-]/[HA].

where,

[A-] is molar concentration of conjugate base and

[HA] is molar concentration of weak acid.

Given,

pH = 5.30

Substitute the value in the Henderson Hasselbalch equation

5.30 = 4.874 + log[A-]/ [HA]

log[A-]/[HA] = 5.30 - 4.874

[A-]/[HA] = 10^ 0.426

[A-]/[HA] = 2.7

Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

Learn more about Henderson Hasselbalch equation here:

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