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3 years ago

The minimum amount of energy that can be absorbed or released by matter is called

Physics

1 answer:

bazaltina [42]3 years ago

4 0

Answer:

Quantum.

Explanation:

Quantum is defined as the discrete quantity of energy proportional in magnitude to the frequency of the radiation it represents.

It is the minimum amount of any physical entity (physical property) involved in an interaction or to put simply, it is defined as the minimum amount of energy that can be absorbed or released by matter.

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For this trajectory, what would the vertical component of acceleration for the module be at time tm=t0−σ=325s? Recall that accel

Karo-lina-s [1.5K]

I think its half of pie so you divid that by 3.14 .

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3 years ago

Read 2 more answers

Use the fact that 1inch=2.54cm and convert 52 inches into the equivalent length in centimeters.

Lelu [443]

Answer:

To convert inches to centimeters, use an easy formula and multiply the length by the conversion ratio.

Since one inch is equal to 2.54 centimeters, this is the inches to cm formula to conver

Explanation:

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2 years ago

You want to lean your dad's ladder on a smooth wall. If the mass of ladder is 4.42 kg and coefficient

iren [92.7K]

Answer:

angle minimum θ = 41.3º

Explanation:

For this exercise let's use Newton's second law in the condition of static equilibrium

N - W = 0

N = W

The rotational equilibrium condition, where we place the axis of rotation on the wall

We assume that counterclockwise rotations are positive

fr (l sin θ) - N (l cos θ) + W (l/2 cos θ) = 0

the friction force formula is

fr = μ N

fr = μ W

we substitute

μ m g l sin θ - m g l cos θ + mg l /2 cos θ = 0

μ sin θ - cos θ + ½ cos θ= 0

μ sin θ - ½ cos θ = 0

sin θ / cos θ = 1/2 μ

tan θ = 1/2 μ

θ = tan⁻¹ (1 / 2μ)

θ = tan⁻¹ (1 (2 0.57))

θ = 41.3º

7 0

3 years ago

The rectangular plates in a parallel-plate capacitor are 0.063 m x 5.4 m. A distance of 3.5 x 10^-5m separate the plates. The pl

Aleks04 [339]

The capacitance of the capacitor is $1.8\cdot 10^{-9}F$

Explanation:

The capacitance of a parallel-plate capacitor is given by the equation

$C=\frac{k\epsilon_0 A}{d}$

where

k is the dielectric constant of the medium

$\epsilon_0 = 8.85\cdot 10^{-12} F/m$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the capacitor in this problem, we have:

k = 2.1 is the dielectric constant

$d=3.5\cdot 10^{-5}m$ is the separation between the plates

$A=0.063m \cdot 0.054m = 0.0034 m^2$ (I assumed that 5.4 m is a typo, since it is not a realistic size for the side of the plate)

Therefore, the capacitance of the capacitor is

$C=\frac{(2.1)(8.85\cdot 10^{-12})(0.0034)}{3.5\cdot 10^{-5}}=1.8\cdot 10^{-9}F$

Learn more about capacitors:

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brainly.com/question/8892837

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#LearnwithBrainly

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3 years ago

What is the difference between a group and a period

Digiron [165]

Periods going left to right. The periodic table also has a special name for its vertical columns. Each column is called a group. The elements in eachgroup have the same number of electrons in the outer orbital.

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3 years ago