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2 years ago

5

Give an example of a normal force. type below.

1 answer:

Oksi-84 [34.3K]2 years ago

8 0

Normal force is the force exerted when an object is on an surface. So an example could be a pile of books on top of a table.

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9.80 1. The density of mercury is 13600 kg/m³. What is this value in g/cm³? 2. Find the mass of water which will fit in a large

My name is Ann [436]

Answer:

1. 13..6 grams per centimeters cubed.

2. Mass = 400kg

3. Volume = 200cm = 2m

Explanation:

1. The conversion for kg/m^3 to g/cm^3 is divide by 1000.

2. $density=\frac{mass}{volume}$

$1000=\frac{mass}{2 * 1 * 0.2}$

$1000*0.4=mass$

$400kg = mass$

3. $density=\frac{mass}{volume}$

$0.6=\frac{120}{volume}$

$volume=\frac{120}{0.6}$

$volume= 200cm$

4 0

1 year ago

What is square rot of 80

guajiro [1.7K]

The square root of 80 is: 8.944

3 0

3 years ago

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A compact car, mass 660 kg, is moving at 1.00 ✕ 102 km/h toward the east. The driver of the compact car suddenly applies the bra

Maslowich

Answer: $59.43\times 10^3 kg-m/s$

Explanation:

Given

mass of car $m=660 kg$

Initial velocity of car $=102 km/h\approx 28.33 m/s$ towards east

Time taken to stop $t=2.1 s$

Force exerted $F_{avg}=4.8\times 10^3 N$

change in momentum is given by impulse imparted to the car

$Impulse(J)=-F\cdot t$

$J=-4.8\times 10^3\times 2.1$

$J=-59.49\times 10^3 kg-m/s$

negative Sign indicates that impulse is imparted opposite to the direction of motion

magnitude of momentum $J=59.49\times 10^3$

6 0

3 years ago

Read 2 more answers

What is one positive outcome of the recent<br>events?

fenix001 [56]

Answer:

Analyze the positive and negative consequences of catastrophic events of the last 40-50 years and the individuals that had an impact on these events. Meaning.

Explanation:

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2 years ago

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A wagon wheel consists of 8 spokes of uniform diamter, each of mass m, and length L. The outer ring has a mass m rin. What is th

Genrish500 [490]

Answer:

$L^2(\dfrac{8m}{3}+m_r)$

Explanation:

m = Mass of each rod

L = Length of rod = Radius of ring

$m_r$ = Mass of ring

Moment of inertia of a spoke

$\dfrac{mL^2}{3}$

For 8 spokes

$8\dfrac{mL^2}{3}$

Moment of inertia of ring

$m_rL^2$

Total moment of inertia

$8\dfrac{mL^2}{3}+m_rL^2\\\Rightarrow L^2(\dfrac{8m}{3}+m_r)$

The moment of inertia of the wheel through an axis through the center and perpendicular to the plane of the ring is $L^2(\dfrac{8m}{3}+m_r)$ .

3 0

3 years ago