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2 years ago

A capacitor is connected to an ac supply. increasing the frequency of the supply _________ the current through the capacitor

1 answer:

5 0

A capacitor is connected to an ac supply. increasing the frequency of the supply increases the current through the capacitor

A capacitor is a device for storing electrical energy that consists of two insulated conductors in close proximity. The parallel-plate capacitor is a simple example of such a storage device.

A capacitor (also known as a condenser) is a two-terminal passive electrical component that stores energy electrostatically in an electric field. Practical capacitors come in a variety of shapes and sizes, but they all have at least two electrical conductors (plates) separated by a dielectric (i.e., insulator).

Capacitors exist in various shapes and sizes, and their value is measured in farads (F). Capacitors are utilized in both alternating current and direct current systems.

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A military helicopter on a training mission is flying horizontally at a speed of 90.0 m/s when it accidentally drops a bomb (for

Elena-2011 [213]

Answer:

1) 10.1 s 2) 909 m 3) 90.0 m/s 4) -99m/s 5) just over the bomb.

Explanation:

In the vertical direction, as the bomb is dropped, its initial velocity is 0.
So, we can find the time required for the bomb to reach the earth, applying the following kinematic equation for displacement:

$\Delta y = \frac{1}{2}*a*t^{2} (1)$

where Δy = -500 m (taking the upward direction as positive).
a=-g=-9.8 m/s²
Replacing these values in (1), and solving for t, we have:

$t =\sqrt{\frac{2*\Delta y}{-g}} = \sqrt{\frac{2*(-500m)}{-9.8m/s2}} = 10.1 s$

The time required for the bomb to reach the earth is 10.1 s.

In the horizontal direction, once released from the helicopter, no external influence acts on the bomb, so it will continue moving forward at the same speed. that it had, equal to the helicopter.
As the time must be the same for both movements, we can find the horizontal displacement just as the product of this speed times the time, as follows:

$x = v_{0x} * t = 90.0 m/s * 10.1 s = 909 m.$

The horizontal component of the bomb's velocity is the same that it had when left the helicopter. i.e. 90 m/s.

In order to find the vertical component of the bomb's velocity just before it strikes the earth, we can apply the definition of acceleration, remembering that v₀ = 0, as follows:

$v_{f} = -g*t = -9.8 m/s2*10.1 s = -99 m/s$

If the helicopter keeps flying horizontally at the same speed, it will be always over the bomb, as both travel horizontally at the same speed.
So, when the bomb hits the ground, the helicopter will be exactly over it.

8 0

4 years ago

frictional force acting on a 0.5 kg object and a floor is 3 N. What is the coefficient of friction between the object and the fl

ikadub [295]

Answer:

μ = 0.6

Explanation:

F = μN

N = mg

F = μmg

3 N = μ*0.5 kg * 9.8 m/s²

μ = 3/(0.5*9.8) = 0.6

7 0

3 years ago

a bird flying horizontally accidently drops a rock it was carrying. 2.10s later,the rocks velocity is 22.2m/s in a -68.2 directi

Mashutka [201]

Answer:

8.24 m/s

Explanation:

Given:

t = 2.10 s

v₀ᵧ = 0 m/s

vₓ = 22.2 cos(-68.2) m/s

aₓ = 0 m/s²

Find: v₀

In the x direction:

v = at + v₀

22.2 cos(-68.2) = (0) (2.10) + v₀ₓ

v₀ₓ = 8.24

v₀² = v₀ₓ² + v₀ᵧ²

v₀² = (8.24)² + (0)²

v₀ = 8.24 m/s

3 0

3 years ago

A ball is thrown vertically downward from the top of a 37.4-m-tall building. The ball passes the top of a window that is 15.4 m

Effectus [21]

Answer:

v= 20.8 m/s

Explanation:

Assuming no other forces acting on the ball, from the instant that is thrown vertically downward, it's only accelerated by gravity, in this same direction, with a constant value of -9.8 m/s2 (assuming the ground level as the zero reference level and the upward direction as positive).
In order to find the final speed 2.00 s after being thrown, we can apply the definition of acceleration, rearranging terms, as follows:

$v_{f} = v_{o} + a*t = v_{o} + g*t (1)$

We have the value of t, but since the ball was thrown, this means that it had an initial non-zero velocity v₀.
Due to we know the value of the vertical displacement also, we can use the following kinematic equation in order to find the initial velocity v₀:

$\Delta y = v_{o} *t + \frac{1}{2} * a* t^{2} (2)$

where Δy = yf - y₀ = 15.4 m - 37.4 m = -22 m (3)

Replacing by the values of Δy, a and t, we can solve for v₀ as follows:

$v_{o} = \frac{(\Delta y- \frac{1}{2} *a*t^{2})}{t} = \frac{-22m+19.6m}{2.00s} = -1.2 m/s (4)$

Replacing (4) , and the values of g and t in (1) we can find the value that we are looking for, vf:

$v_{f} = v_{o} + g*t = -1.2 m/s - (9.8m/s2*2.00s) = -20.8 m/s (5)$

Therefore, the speed of the ball (the magnitude of the velocity) as it passes the top of the window is 20.8 m/s.

4 0

3 years ago

What magnitude impulse will give a 2.0 kg object a momentum change of magnitude 50 kg m/s?

tatyana61 [14]

The answer is +50Ns,

Impulse equals force (final time – initial time)

impulse = f * Δt

I = is a symbol for an impulse.

F = is a symbol for an object's force.

t = denotes the passage of time.

Due to the fact that the impulse is a measurement of how much the momentum alters as a result of a force acting on it over time. Derivation of Impulse: Impulse = p = p final - p initial .P refers to the momentum change.the final momentum is denoted by p final.the initial momentum is denoted by p initial .The formula's connection between impulse and an object's change in momentum is its most notable feature. Additionally, impulse can be measured in either kilogram meters per second (kg m/s) or Newton second.

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4 0

2 years ago