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Artist 52 [7]
3 years ago
11

Increasing the concentration of greenhouse gases in Earth's atmosphere decreases the transparency of the atmosphere to infrared

light. decreases the transparency of the atmosphere to visible light. increases the transparency of the atmosphere to visible light. increases the transparency of the atmosphere to infrared light. Which of the following statements about global warming is NOT true? Computer models indicate that only human contributions to atmospheric carbon dioxide can account for recent global temperature rises Atmospheric carbon dioxide levels have risen dramatically over the past hundred years or so. Rises in global mean temperature tend to be closely associated with rises in atmospheric carbon dioxide concentrations. The global mean temperature in the modern era is the highest is has ever been
Physics
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

Decrease the transparency of the atmosphere

Explanation:

Different gases have characteristic absorption bands, so-called greenhouse gases have very high bands in the infrared region and small bands in the region of visible light.

   When the radiation  arrives to pass the greenhouse gases (CO²) and affects the earth's surface after several processes, the earth emits radiation in the infrared region, but this is absorbed by the gases, creating a net heating, since that the transparency of the atmosphere is  DECREASE for infrared radiation

Reviewing the correct answers is: Decrease the transparency of the atmosphere

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A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3 /s. determine the minimum power that must be suppl
ELEN [110]
Given:
ρ = 1.18 kg/m³, density of air
v = 8 m/s, flow velocity
Q = 9 m³/s, volumetric flow rate

The minimum power required (at 100% efficiency) is
\frac{1}{2} (8 \,  \frac{m}{s} )^{2}*(9 \,  \frac{m^{3}}{s} )*(1.18 \,  \frac{kg}{m^{3}}) =  339.84 \, W

The actual power will be higher because 100% efficiency is not possible.

Answer: 339.8 W (nearest tenth)
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What is surface tension ​
harina [27]

Answer:

Surface tension is,  the surface where the water meets the air, water molecules cling even more tightly to each other.

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3 years ago
Un avión que sale del aeropuerto de mexico a las 7 horas con o min aterriza en la ciudad de Bogotá, Colombia a las 11 horas con
Vitek1552 [10]

4095km

Explanation:

Given parameters:

Starting time = 7 o'clock

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Speed  = 910km/hr

Unknown:

Distance covered = ?

Solution:

Speed is the rate of change of distance with time.

It is a scalar quantity that is with respect with magnitude but no direction.

 Speed = \frac{distance}{time}

 Distance = Speed x time

Time taken = time between 11hrs 30min and 7 o'clock = 4.5hrs

  Input the parameters:

  Distance = 910km/hr x 4.5hrs = 4095km

learn more:

Speed brainly.com/question/10048445

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6 0
3 years ago
Can fly but have no wings. I can cry but I have no eyes. Wherever I go, darkness follows me. What am I? I will give brainiest if
nalin [4]

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Explanation:

Clouds float in the sky but do not have wings like a bird or plane.

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4 0
3 years ago
Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
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