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jenyasd209 [6]
2 years ago
15

An object is attached to a vertical ideal massless spring and bobs up and down between the two extreme points A and B. When the

kinetic energy of the object is a minimum, the object is located Group of answer choices
Physics
1 answer:
nekit [7.7K]2 years ago
7 0

In SHM the Kinetic energy is maximum at the mean position and the Kinetic energy is minimum at the extreme points, hence the kinetic energy is minimum at either A or B.

<h3>What is simple harmonic motion?</h3>

In mechanics and physics, simple harmonic motion is a special type of periodic motion where the restoring force on the moving object is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position

kinetic energy - The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

to learn more about simple harmonic motion go to - brainly.com/question/20885248

#SPJ4

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Deduce the relation between kwh and joule define 1 watt​
dimulka [17.4K]

Explanation:

We know that kWh is a commercial unit of energy.

Also, 1 Joule = 1 watt × 1 seconds

1\ kWh=1kW \times 1\ h

Since ,1 h = 3600 s and 1kW = 1000 W

1\ kWh=1000\ W \times 3600\ s\\\\1\ kWh = 36\times 10^5\ W-s\\\\1\ kWh=36\times 10^5\ J

So, the relation is : 1\ kWh=36\times 10^5\ J

1 watt is defined as the power of an appliance when the energy is transferred at a rate of 1 Joule per second.

5 0
3 years ago
Venn diagrams are used for comparing and contrasting topics. The overlapping sections show characteristics that the topics have
tangare [24]

Answer:

Carry energy and follow a pattern

5 0
3 years ago
Read 2 more answers
A block of mass m slides down a frictionless track, then around the inside of a circular loop-the-loop of radius R. From what mi
Oliga [24]

Answer:

H = \frac{5}{2}R

Explanation:

As we know that if the block will complete the circular motion of the path then the speed at the bottom most part of the path must be equal to

v = \sqrt{5Rg}

now we know that

velocity at the bottom of the path is due to conversion of potential energy to kinetic energy

so we can say it is given as

U = KE

mgH = \frac{1}{2}mv^2

now we have

mgH = \frac{1}{2}m(5Rg)

H = \frac{5}{2}R

3 0
3 years ago
A piano wire with mass 3.00 g and length 80.0 cm is stretched with a tension of 25.0 N. A wave with frequency 120.0 Hz and ampli
lys-0071 [83]

Answer:

(a) P_{avg} = 0.22 W

(b) P_{avg,2} = 0.056 W

Explanation:

given information:

the mass of piano wire, m = 3.00 g = 0.003 kg

tension, F = 25 N

length, l = 80 cm = 0.8 m

frequency, f = 120 Hz

amplitude, A = 1.6 mm = 0.0016 m

(a) the average power carried by the wave, P_{avg}

P_{avg} = \frac{1}{2}(√μF)ω²A²

where,

ω = 2πf = 2π120 = 754s^{-1}

μ = \frac{m}{l}

  = \frac{0.003}{0.8}

  = 0.00375 kg/m

thus,

P_{avg} = \frac{1}{2}(√(0.00375)(25))(754)²(0.0016)²

P_{avg} = 0.22 W

(b) What happens to the average power if the wave amplitude is halved.

based on the equation above, we know that the average power is proportional to the square amplitude. therefore

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{A_{2} ^{2} } }

\frac{P_{avg,1} }{P_{avg,2} } = \frac{A_{1} ^{2} }{(0.5A_{1} )^{2} } }

P_{avg,2} = \frac{0.22}{4}

P_{avg,2} = 0.056 W

4 0
3 years ago
Arm
Daniel [21]
Can't say for sure but I think it's a) or c)
3 0
4 years ago
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