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1 year ago

This equation shows how the total number of postcards Jared buys is related to the number of days he spends on vacation.

Mathematics

1 answer:

Brums [2.3K]1 year ago

5 0

Answer:

Postcards bought was 9

Step-by-step explanation:

where,

P = total number of postcards
D = days of vacation = 3 days

⟼ P = 3D

prince number of days of vacation is 3 therefore we multiply 3 by 3

⟼ P = 3(3)

multiply 3 by 3

⟼ P = 9

$\therefore$ Jared bought 9 postcards

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Does anyone know how to do these maths question???

Dmitry_Shevchenko [17]

Answer:

Part 1) $f(g(x))=3(x^2)+2$

Part 2) $g(f(5))=289$

Step-by-step explanation:

we know that

A composite function is a function that depends on another function. A composite function is created when one function is substituted into another function

we have

$f(x)=3x+2$

$g(x)=x^{2}$

Part 1) Determine f(g(x))

To find f(g(x)) substitute the function g(x) as the variable in function f(x)

$f(g(x))=3(x^2)+2$

Part 2) Determine g(f(x))

To find g(f(x)) substitute the function f(x) as the variable in function g(x)

$g(f(x))=(3x+2)^2$

For x=5

$g(f(5))=(3(5)+2)^2$

$g(f(5))=289$

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2 years ago

Which expression is not equivalent to 8+(n-4)

MrRa [10]

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2 years ago

According to a recent publication, the mean price of new mobile homes is $63 comma 800. Assume a standard deviation of $7900.

wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,580, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are $63,800 and $1,117, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}$

For n=25 we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580$

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

$\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117$