Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
v=9i+3j
40 dollars they each spent 40 dollars from 70 dollars
Answer:
The system of equations has one solution. The two equations are intersecting lines.
Step-by-step explanation:
if you want to use the substitution method, you would have to plug in y for 12x+2 in the second equation.
2(12x+2)=x+4
next, you have to distribute
24x+4=x+4
subtract 24x from each side
4=-23x+4
subtract 4 from each side
0=23x
divide each side by 23
x=0
now, plug in 0 to one equation.
y=12(0)+2
y=2
the lines intersect at one point, (0,2)
Y=3/1x+-1 hope this is correct
