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VladimirAG [237]
2 years ago
9

What is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of

the compound are provided?
Chemistry
1 answer:
Natasha_Volkova [10]2 years ago
5 0

Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

<h3>What is Empirical Formula ? </h3>

The Empirical formula is the simplest whole number ratio of atoms present in given compound.

<h3>What is Molecular formula of Compound ?</h3>

Molecular Formula = Empirical Formula × n

n =  \frac{\text{Molar Mass}}{\text{Empirical Formula weight}}

Thus from the above conclusion we can say that Mass percentages of the the elements in the compound is the only additional information needed to calculate the empirical formula of a compound if the masses of each element of the compound are provided.

Learn more about Empirical Formula here: brainly.com/question/1603500

#SPJ4

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PLSSS HELPPPPPPPP. I will give brainliest
nasty-shy [4]

Answer:

Ionic bond

Explanation:

Covalent bonds can only form between non-metals and copper is a metal so it would be an ionic bond.

6 0
3 years ago
Which element has chemical properties that are most similar to those of calcium?
iris [78.8K]
I think the answer is (1) Co. Because the element of Cobalt also has 2 electrons at the outer layer which is the same as Calcium. And the outer layer is an important factor which can affect the property of an element.
3 0
4 years ago
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Calculate with the correct number of significant figures 2.0 x 10^5 x 3.00 x 10^8
xxMikexx [17]

Answer:

the correct answer is 17 significant figures

3 0
3 years ago
In the laboratory a student determines the specific heat of a metal. He heats 19.5 grams of copper to 98.27 °C and then drops it
siniylev [52]

Answer:

The specific heat of copper is 0.37 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of copper = 19.5 grams

Initial temperature of copper = 98.27 °C

Mass of water = 76.3 grams

Initial temperature of water = 24.05 °C

Final temperature of water and copper = 25.69 °C

<u>Step 2:</u> Calculate specific heat of copper

Qgained = -Qlost

Q = m*c*ΔT

Qwater = -Qcopper

m(water) * c(water) * ΔT(water) = - m(copper) * c(copper) *ΔT(copper)

⇒ with m(water) = 76.3 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2-T1 = 25.69 - 24.05 = 1.64

⇒ with m(copper) = 19.5 grams

⇒ with c(copper) = TO BE DETERMINED

⇒ with ΔT(copper) = T2-T1 = 25.69 - 98.27 = -72.58

76.3 * 4.184 * 1.64 = - 19.5 * c(copper) * -72.58

523.552 = 1415.31 * c(copper)

c(copper) = 0.37 J/g°C

The specific heat of copper is 0.37 J/g°C

3 0
3 years ago
Does a bucket of water and an ice cube have the same chemical properties?
leva [86]
No, their specific heats are different. For water, and ice
3 0
3 years ago
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