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jolli1 [7]
2 years ago
15

Based on its type of chemical bond, which substance has the highest boiling point?

Chemistry
2 answers:
Aleonysh [2.5K]2 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

When a compound contains a strong bond between its combining atoms or molecules then the compound will have a high boiling point.

An ionic bond is a strong bond because it contains strong force of attraction between two oppositely charged atoms.  

For example, LiF is an ionic compound in which lithium is Li^{+} ion and fluorine is F^{-} ion.

Therefore, LiF compound will have strong force of attraction.

On the other hand, covalent compounds have weak bond due to sharing of electrons. Hence, they have low boiling point.

For example, CO_{2}, CCl_{4}, and H_{2} etc are covalent compounds.

Thus, we can conclude that LiF substance has the highest boiling point.

Ber [7]2 years ago
7 0
Answer: Lithium Fluoride

Explanation: Let’s see,,,
1. Obviously not hydrogen or carbon dioxide because they’re gas at room temp.
2. Lithium Fluoride is an ionic compound which means they have higher intermolecular forces and require more energy to break them, so it probably has a higher boiling point.
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Answer:

m_{HCl}=36.1gHCl

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required grams of HCl by firstly identifying the limiting reactant via the moles of each reactant as they are in a 1:1 mole ratio:

n_{H_2}=1.00gH_2*\frac{1molH_2}{2.02gH_2}=0.500molH_2\\\\ n_{Cl_2}=55.0gCl_2*\frac{1molCl_2}{70.9gCl_2}=0.776molCl_2

Thus, we infer the hydrogen is the limiting reactant and therefore we use its 1:2 mole ratio with HCl whose molar mass is 36.46 g/mol:

m_{HCl}=0.500molH_2*\frac{2molHCl}{1molH_2}*\frac{36.46gHCl}{1molHCl}\\\\m_{HCl}=36.1gHCl

Regards!

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C is the answer.

It says on the third picture that Bohr refined Rutherford's model by giving distinct orbits for the electrons with distinct radii.


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Answer: 1.24 × 10^25

Explanation:

\frac{20.6 moles}{1} × \frac{6.022 * 10^{24} }{1 Mole}

Using our knowledge in unit conversions, we know the mole units cancel each other out and all there's left is the atom unit. From here we can multiply the fractions and eventually we end with the number 124.0532 × 10^23

According to the scientific notation rules, the number to the left of the decimal cannot exceed 10 so we have to move the decimal to the left two spaces. With this change, we also have to change the exponent of the 10. Because we moved the decimal point two spaces to the left, that means we have 10^25.

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