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aliina [53]
2 years ago
7

What would be the greatest effect of the finite size of molecules on the ideal gas law?

Physics
1 answer:
Musya8 [376]2 years ago
8 0

At high density of the molecules tends to be greater pressure that of molecules and at low density of the molecules tends to be less pressure that of molecules.

It is given that the molecules are in the ideal gas.

It is required to find the greatest effect of the finite size of molecules on the ideal gas law.

<h2>What would be the greatest effect of the finite size of molecules on the ideal gas law?</h2>

According to ideal gas law, at high density of the molecules tends to be greater pressure that of molecules and at low density of the molecules tends to be less pressure that of molecules.

From ideal gas equation,

PV = nRT

Where,

P - Pressure of the molecules

V - Volume of the molecules

n - Total amount of substance

R - Gas constant

T - Temperature of the molecules

As shown from above equation, both the quantities are directly proportional to each other and also ideal gas law follows the kinetic molecular theory  where it suggests that the volume of the molecules have negligible point.

Thus, at high density of the molecules tends to be greater pressure that of molecules and at low density of the molecules tends to be less pressure that of molecules.

Learn more about the ideal gas here:

brainly.com/question/8711877

#SPJ4

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Answer:

82.25 moles of He

Explanation:

From the question given above, the following data were obtained:

Volume (V) = 10 L

Mass of He = 0.329 Kg

Temperature (T) = 28.0 °C

Molar mass of He = 4 g/mol

Mole of He =?

Next, we shall convert 0.329 Kg of He to g. This can be obtained as follow:

1 Kg = 1000 g

Therefore,

0.329 Kg = 0.329 Kg × 1000 g / 1 Kg

0.329 Kg = 329 g

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Mass of He = 329 g

Molar mass of He = 4 g/mol

Mole of He =?

Mole = mass / molar mass

Mole of He = 329 / 4

Mole of He = 82.25 moles

Therefore, there are 82.25 moles of He in the tank.

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