Question

(Repost) I need help with this physics question. Thanks in advance! Answer ASAP.

Answer 1

The time taken for the tiny saliva to travel is 0.55 second.

The  horizontal distance traveled at speed of 4 m/s is 2.2 m.

The horizontal distance traveled at speed of 20 m/s is 11 m.

Time of motion of the tiny saliva

The time taken for the tiny saliva to travel is calculated as follows;

h = vt + ¹/₂gt²

where;

• v is initial vertical velocity  = 0
• g is the acceleration due to gravity

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

Substitute the given parameters and solve for time of motion;

t = √(2 x 1.5 / 10)

t = 0.55 second

Horizontal distance traveled at speed of 4 m/s

X = Vx(t)

X = (4 m/s)(0.55)

X = 2.2 m

Horizontal distance traveled at speed of 20 m/s

X = (20)(0.55)

X = 11 m

Learn more about time of motion here: brainly.com/question/2364404

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