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zzz [600]
4 years ago
6

Most comets come from an area called the oort cloud true or false

Physics
2 answers:
KiRa [710]4 years ago
8 0
The statement is constructed with the purest form of veracity, and
it is True in every respect, every jot and tittle, ever 'p' and 'q'.
Truer words are rarely if ever spoken.  Verily and forsooth,
Most comets indeed come from a dark, distant, foreboding
place in the solar system, unknown until very recently, and
now referred to as the "Oört Cloud". 
Firdavs [7]4 years ago
4 0

Answer:

True

Explanation:

Oort cloud is an icy region. It is named after a Dutch Astronomer who discovered it, theoretically. It is a spherical region that stretches far beyond Pluto, in our Solar system.

The region over which it stretches beyond the Sun is estimated to be about one and half light years and more. Temperatures are between 0 C to 4 C, in that region. Comets, ice chunks planetesimals are all a part of that region. These exist in  huge numbers.

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A rollerblader is blading along the sidewalk. Which forms of measurement would be the best to use to determine the rollerblader'
Greeley [361]
You would use distance an time formula to mathmaticly solve

3 0
3 years ago
a constant force acts on an object of mass 10 kg for a duration of 2 seconds it increases the object velocity from 4metre per se
inn [45]

Answer:

F=ma

a=v/t

a=vf-vi/t

a=8-4/2

a=4÷2

a=2msec*2

F=10×2

F=20N

3 0
3 years ago
A industrial (large) pressure cooker operates at 275 kPa. Initially there is 10 kg of water at 20°C, the cooker is operated unt
alex41 [277]

Answer:

Q_{in} = 25349.92\,kJ

Explanation:

Let establish a control volume in the industrial pressure cooker, which is a transient state system. From the First Law of Thermodynamics, the heating process is modelled:

Q_{in} + m_{1}\cdot h_{1} - m_{2}\cdot h_{2} = (m_{1}-m_{2})\cdot u_{2} - m_{1}\cdot u_{1}

The heat transfered to the cooker is:

Q_{in} = m_{2}\cdot h_{2} - m_{1}\cdot h_{1} + (m_{1}-m_{2})\cdot u_{2}-m_{1}\cdot u_{1}

Properties at each state are described below:

State 1

u_{1} = 83.913\,\frac{kJ}{kg}

h_{1} = 83.915\,\frac{kJ}{kg}

State 2

u_{2} = 2540.1\,\frac{kJ}{kg}

h_{2} = 2720.9\,\frac{kJ}{kg}

The heat transfered to the cooker is:

Q_{in} = (9\,kg)\cdot (2720.9\,\frac{kJ}{kg} ) - (10\,kg)\cdot (83.915\,\frac{kJ}{kg} ) + (1\,kg) \cdot (2540.1\,\frac{kJ}{kg} )-(10\,kg)\cdot (83.913\,\frac{kJ}{kg} )

Q_{in} = 25349.92\,kJ

7 0
3 years ago
You find a measurement or 34 kg written in a laboratory notebook. What physical characteristic is this a measurement of?
Elis [28]
Planck's constant. A physical constant adopted in 2011 by the CGPM.
7 0
4 years ago
A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is oriented
oee [108]

Answer:

Magnetic flux, \phi=2.22\times 10^{-3}\ Wb

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

\phi=BA\ cos\theta

\phi=0.078\times \pi \times (0.1)^2\ cos(25)

\phi=0.00222\ Wb

or

\phi=2.22\times 10^{-3}\ Wb

So, the magnitude of magnetic flux through the surface is 2.22\times 10^{-3}\ Wb. Hence, this is the required solution.

4 0
3 years ago
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