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zzz [600]
3 years ago
6

Most comets come from an area called the oort cloud true or false

Physics
2 answers:
KiRa [710]3 years ago
8 0
The statement is constructed with the purest form of veracity, and
it is True in every respect, every jot and tittle, ever 'p' and 'q'.
Truer words are rarely if ever spoken.  Verily and forsooth,
Most comets indeed come from a dark, distant, foreboding
place in the solar system, unknown until very recently, and
now referred to as the "Oört Cloud". 
Firdavs [7]3 years ago
4 0

Answer:

True

Explanation:

Oort cloud is an icy region. It is named after a Dutch Astronomer who discovered it, theoretically. It is a spherical region that stretches far beyond Pluto, in our Solar system.

The region over which it stretches beyond the Sun is estimated to be about one and half light years and more. Temperatures are between 0 C to 4 C, in that region. Comets, ice chunks planetesimals are all a part of that region. These exist in  huge numbers.

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6 0
3 years ago
Water is entering the prism at a rate of A m^3/hr. The prism is empty at time 0. Express the depth d of the water in meters in t
zavuch27 [327]

This question is incomplete, the complete question is;

The picture shows a triangular prism. The end of prism are equilateral triangles with x meters. the other dimension of the prism is L meters

a) Find the volume V in terms of x and L

b) Water is entering the prism at a rate of A m³/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.  

Answer:

a) the volume V in terms of x and L is  ((√3/4)x²L) m³

b) required expression is (2/(3)^(1/u))√(At/L)

Explanation:

Given that;

form the question and image below;

triangular prism ends are equilateral triangle

side length = x meter

Dimension of the prism = L meter

Area of the equilateral triangle = √3/4 (side)² = √3/4 (x)² meter

Volume of the triangular prism = Area × height

= √3/4 (x)² × L

V = ((√3/4)x²L) m³

Therefore, the volume V in terms of x and L is  ((√3/4)x²L) m³

b)

Rate of water entering = A m³/hr

Depth of water tank = d meter

Time = t

Length of prism = L

now Rate of water entering is A m³/hr

dv/d = A                             [  V = ((√3/4)x²L) m³ ]

and

dv/dt = √3/4 [2x dx/dt ] L                   { L is constant }

so

A = √3/4 [2x dx/dt ] L  

∫A dt = √3/2 [ Lx dx ]                   { Integrate both sides}

At = √3/2 × Lx × x²/2

x² = uAt / √3L                              { we find square root of both sides}

x = √( uAt / √3L )

x = (2/(3)^(1/u))√(At/L)

Therefore; required expression is (2/(3)^(1/u))√(At/L)

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Read 2 more answers
Can some please help me with this?
Lerok [7]

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Hope this helps :)

6 0
3 years ago
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