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sergiy2304 [10]
2 years ago
15

A sample of ch4o with a mass of 32.0 g contains __________ molecules of ch4o. group of answer choices 5.32 ´ 10-23 1.00 1.88 ´ 1

022 6.02 ´ 1023 32.0
Chemistry
1 answer:
LekaFEV [45]2 years ago
3 0

The correct option is (C) 6.02 X 10²³

A sample of CH₄O with a mass of 32.0 g contains <u>6.02 X 10²³</u> molecules of CH₄O.

To calculate the number of moles;

Molar mass of CH₄O = C + 4(H) + O

          = 12.01 + 4(1.008) + 16

          = 32.04 g/mol

So, 1 mol of CH₄O = 32.04 g of CH₄O

Given, 32.0 g of CH₄O

According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).

 = (32.0 g/1)(1 mol CH₄O/32.04 g CH₄O)(6.02x10²³/1 mol CH₄O)

 = 6.02 X 10²³ molecules of CH₄O

Hence, a sample of  will contain  number of molecules 6.02 X 10²³ molecules.

Learn more about the Moles calculation with the help of the given link:

brainly.com/question/21085277

#SPJ4

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0.054 mol O

Explanation:

<em>This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar): CH₃CO₂H. An analytical chemist has determined by measurements that there are 0.054 moles of carbon in a sample of acetic acid. How many moles of oxygen are in the sample?</em>

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Step 1: Given data

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Step 2: Establish the appropriate molar ratio

According to the chemical formula, the molar ratio of C to O is 2:2.

Step 3: Calculate the moles of oxygen in the sample

We will use the molar ratio to determine the moles of oxygen accompanying 0.054 moles of carbon.

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The synthesis of nitrogen trihydride from nitrogen gas and hydrogen gas is shown by which balanced chemical equation?
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How many atoms are in 5 grams of H2O?
mojhsa [17]

Hello!

We know that by the Law of Avogrado, for each mole of substance we have 6.02 * 10²³ atoms, if:

The molar mass of water (H2O)

H = 2 * (1u) = 2u

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---------------------------

The molar mass of H2O = 2 + 16 = 18 g / mol

If:

1 mol we have 6.02 * 10²³ atoms

1 mole of H2O we have 18 g

Then we have:

18 g ------------- 6.02 * 10²³ atoms

5 g -------------- x

\dfrac{18}{5} = \dfrac{6.02*10^{23}}{x}

18*x = 5*6.02*10^{23}

18\:x = 3.01*10^{24}

x = \dfrac{3.01*10^{24}}{18}

\boxed{\boxed{x \approx 1.672*10^{23}\:atoms}}\end{array}}\qquad\checkmark

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