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sergiy2304 [10]
2 years ago
15

A sample of ch4o with a mass of 32.0 g contains __________ molecules of ch4o. group of answer choices 5.32 ´ 10-23 1.00 1.88 ´ 1

022 6.02 ´ 1023 32.0
Chemistry
1 answer:
LekaFEV [45]2 years ago
3 0

The correct option is (C) 6.02 X 10²³

A sample of CH₄O with a mass of 32.0 g contains <u>6.02 X 10²³</u> molecules of CH₄O.

To calculate the number of moles;

Molar mass of CH₄O = C + 4(H) + O

          = 12.01 + 4(1.008) + 16

          = 32.04 g/mol

So, 1 mol of CH₄O = 32.04 g of CH₄O

Given, 32.0 g of CH₄O

According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).

 = (32.0 g/1)(1 mol CH₄O/32.04 g CH₄O)(6.02x10²³/1 mol CH₄O)

 = 6.02 X 10²³ molecules of CH₄O

Hence, a sample of  will contain  number of molecules 6.02 X 10²³ molecules.

Learn more about the Moles calculation with the help of the given link:

brainly.com/question/21085277

#SPJ4

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An impure sample of benzoic acid (C 6H 5COOH, 122.12 g/mol) is titrated with 0.2099 M NaOH. A 1.021-g sample requires 35.73 mL o
Finger [1]

Answer:

The percent by mass of benzoic acid = 89.7 %

Explanation:

Step 1: Data given

Molarity of NaOH = 0.2099 M

Mass of the sample = 1.021 grams

Volume of NaOH = 35.73 mL = 0.03573 L

Step 2: The balanced equation

C6H5COOH(aq) + NaOH(aq) → NaC6H5COO(aq) + H2O(l)

Step 3: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.2099 * 0.03573 L

Moles NaOH = 0.00750 moles

Step 3: Calculate moles benzoic acid

From your balanced equation - benzoic acid reacts in 1:1 molar ratio with NaOH  

The sample must have contained 0.00750 moles benzoic acid  

Mass benzoic acid in 0.00750 moles  = 0.00750 * 122.12 = 0.9159 g benzoic acid  

Mass % acid in sample =  0.9159/1.021 * 100 = 89.7% purity.

The percent by mass of benzoic acid = 89.7 %

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3 years ago
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