First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Answer:
0.1828g/cm³
Explanation:
density= mass÷volume
m= 12.6g
v= 4.1×4.1×4.1 = 68.921cm³
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density= 12.6÷68.921 = 0.1828g/cm³
Answer:
Option c. Neutral
Explanation:
Only neutral solution gives a green colouration to a pH paper
Answer:
Therefore, the rate of change in the amount of salt is 

Explanation:
Given:
Initial volume of water
lit
Flowing rate = 5 
The rate of change in the amount of salt is given by,
( Rate of salt enters tank - rate of sat leaves tank )
Since tank is initially filled with water so we write that,

Let amount of salt in the solution is
,


Therefore, the rate of change in the amount of salt is 
