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Shkiper50 [21]
2 years ago
7

If Matteo has a model car with a volume of 100 mL and a mass of 200 g, what is the density of their model car?

Chemistry
1 answer:
OLEGan [10]2 years ago
6 0

Answer:

<h2>2 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{200}{100}  \\

We have the final answer as

<h3>2 g/mL</h3>

Hope this helps you

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A sample of helium gas at 27.0 °C and 3.60 atm pressure is cooled in the same container to a temperature of -73.0 °C. What is th
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Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm

Explanation:

To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K

Putting values in above equation, we get:

\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm

Thus the new pressure, if volume and amount of gas do not change is  2.40 atm

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3 years ago
Best example of heterogeneous mixture
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why is it essential to know the water temperature in this experiment- to find the vapor pressure of the water
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Vapour pressure of a liquid varies with temperature

Explanation:

The vapour pressure of any liquid is directly proportional to the temperature of the liquid. This implies that, as the temperature of the liquid increases, the vapour pressure increases likewise and vice versa.

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sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a
Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

P_1T_2=P_2T_1

Where, T_1 and T_2 are initial and final temperatures, P_1 and P_2 are initial and final pressures.

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T_2 = -2.0 + 273.15 = 271.15 K

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T_2  = ?

Let's plug in the values in the equation and solve it for final pressure.

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P_2 = 0.942 atm

So, the new pressure of the jar is 0.942 atm.


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3 years ago
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