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tigry1 [53]
1 year ago
14

What is the product of a reaction between a strong acid and a sulfite ion (which acts as a base)?

Chemistry
1 answer:
melamori03 [73]1 year ago
3 0

SO_{2} is the product of a reaction between a strong acid and a sulfite ion (which acts as a base).

A chemical reaction in which an acid and a base interact quantitatively is known as neutralisation or neutralisation. By neutralising a reaction in water, surplus hydrogen or hydroxide ions are removed from the solution.

Despite being a weak base, the sulfite ion can hydrolyze to form basic solutions. The equilibria in an acidic solution are changed to create sulphurous acid, which leads to the development of SO2 gas. A colourless gas with a distinctive suffocating smell, sulphur dioxide.

The reaction mechanism is as follows;

SO_{3}^{2-} (aq) + H_{2} O(l) ⇒ HSO_{3} ^{-} (aq) + OH^{-} (aq)

HSO_{3} ^{-} (aq) + H_{2} O(l) ⇒ H_{2} SO_{3} (aq) + OH^{-} (aq)

H_{2} SO_{3} (aq) ⇒ H_{2} O (l) + SO_{2} (g)

Therefore, SO_{2} is the product of a reaction between a strong acid and a sulfite ion (which acts as a base).

Learn more about neutralization reaction here:

brainly.com/question/15095136

#SPJ4

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BARSIC [14]

Answer:

Explanation:

a ) one mole = 6.02 x 10²³ atoms

no of moles in given no of atoms

= 8 x 10⁹ / 6.02 x 10²³

= 1.329 x 10⁻¹⁴ moles .

b ) one mole of calcium = 40 gram

102 .5 g calcium

= 102 .5 / 40 moles

= 2.5625 moles

c )

no of moles in 5.04 g lead = 5.04 / 207

= 2.4347 x 10⁻² moles

= 2.4347 x 10⁻²x 6.02 x 10²³ no of atoms of lead

= 14.6568 x 10²¹ no of atoms .

d)  

one mole = 6.02 x 10²³ atoms

2.85 mole = 17.157 x 10²³ atoms .

e )

moles of fluorine gas = 1.08 x 10³ / 6.02 x 10²³

= .1794 x 10⁻²⁰ moles

mass in grams =  .1794 x 10⁻²⁰ x 38

= 6.8172 x 10⁻²⁰ grams

f )

no of moles in .584 g of benzene = .584 / 78

= 7.487 x 10⁻³ moles

no of molecules = 6.02 x 10²³ x  7.487 x 10⁻³

= 45.07 x 10²⁰ molecules .

g )

moles of atoms = 5.09 x 10⁹ / 6.02 x 10²³

= .8455 x 10⁻¹⁴ moles

mass in gram = .8455 x 10⁻¹⁴ x 1

=  .8455 x 10⁻¹⁴ g

h )

.45 moles of Ca₃PO₄ = .45 x 6.02 x 10²³ molecules

= 2.709 x 10²³ molecules of Ca₃PO₄

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7 0
3 years ago
How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci
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Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ +  2HCl  →  CaCl₂  + CO₂  +  H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

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Answer:

Molarity.

Explanation:

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M = (mass / molar mass) of the solute (1000 / volume of the solution).

<em>So, the best measurement of concentration for describing the concentration of a solid solute dissolved in one liter of a liquid solution is Molarity.</em>

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