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ICE Princess25 [194]
3 years ago
6

3! + 0! / 2! * 1! = a). 3/2 b). 3 c). 7/2 Pls i need help quick

Mathematics
2 answers:
Savatey [412]3 years ago
8 0
3!=6
0!1
2!=2
1!=1
6+1/2*1=6.5
The answer isn't given.
Vilka [71]3 years ago
8 0

Answer:

c). 7/2

Step-by-step explanation:

\tt\cfrac{3!+0!}{2!\cdot1!}= \cfrac{3\cdot2\cdot1+1}{2\cdot1\cdot1}=\cfrac{6+1}{2}=\cfrac{7}{2}

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B: -2

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3 0
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In a carnival​ game, the player selects a ball one at a​ time, without​ replacement, from an urn containing twotwo purplepurple
dezoksy [38]
<span>The urn contains 2 purple balls and 4 white balls. The player pay $4 for start the game and get $1.5 for every ball drawn until one purple ball is drawn. The maximal revenue would be $7.5 when 4 white balls and 1 purple balls are drawn.
If the purple ball is p and white ball is w, t</span>he possible sample space of drawings are {p, wp, wwp, wwwp, wwwwp}

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p= 2/6
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wp= (4*2)/(6*5) = 4/15
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wwp= (4*3*2)/(6*5*4)= 1/5
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The expected value would be:
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6 0
3 years ago
Can some help me with this problem
Y_Kistochka [10]

Answer:

580

Step-by-step explanation:

4*100=400

4*40=160

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add them all up, you get 580

7 0
3 years ago
Read 2 more answers
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Arte-miy333 [17]
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