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arsen [322]
3 years ago
14

Consider two parallel wires carrying current in the same direction. Which one of the following statements is true concerning thi

s situation?
A) The two wires will attract each other, even if no external magnetic field is applied to the wires.
B) The two wires will repel each other, even if no external magnetic field is applied to the wires.
C) The two wires will attract each other only if an external magnetic field is applied to the wires.
D) The two wires will repel each other only if an external magnetic field is applied to the wires.
E) The wires will be neither attracted nor repelled from each other when no external magnetic field is applied to the wires.
Physics
1 answer:
Sedbober [7]3 years ago
3 0

Answer:A the two wire will attract each other

Explanation:

When current is flowing in a wire it is surrounded by magnetic field whose direction can be given by right hand thumb rule.

If current is in direction of your thumb then wrapping of fingers will give the direction of magnetic field.

If two wires with current in same direction flows then the combined  magnetic field will be constructive in nature and thus they attract each other.

force on second wire due to first wire is

F_{21}=I_2\vec{L_2}\times B_1 which will be towards the first wire

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Identify the factors that cause melting and thus the formation of magma. Choose one or more: A. decompression B. compression C.
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Answer: C Heat Transfer, E Addition of Volatiles and A Decompression

Explanation:

- Decompression melting takes place within Earth when a body of rock is held at approximately the same temperature but the pressure is reduced.

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Compare animal and plant cell
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Answer:

A plant cell contains a large, singular vacuole that is used for storage and maintaining the shape of the cell. In contrast, animal cells have many, smaller vacuoles. Plant cells have a cell wall, as well as a cell membrane. Animal cells simply have a cell membrane, but no cell wall.

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8 0
3 years ago
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A 0.0250-kg bullet is accelerated from rest to a speed of 550 m/s in a 3.00-kg rifle. The pain of the rifle’s kick is much worse
kondaur [170]

Answer:

a) 4.583 m/s

b) 31.505 J

c) 0.491 m/s

d) 3.375 J

e)

   p_player = (110 kg)(8 m/s) = 880 kg m/s

   p_ball = (0.41 kg)(25 m/s) = 10.25 kg m/s

Explanation:

HI!

a)

We can calculate the recoil velocity by conservation of momentum, remember that p=mv.

The momentum of the bullet is:

p_b = (0.0250 kg)*(550 m/s )

The momentum of the rifle is:

p_r = (3 kg) * v

Since the total initial momentum is zero:

p_b = p_r

That is:

v = (550 m/s ) (0.0250 kg/ 3 kg ) = 4.583 m/s

b)

The kinetic energy gained by the rifle is:

K = (1/2) m v^2 = (1/2) *(3 kg) *(4.583 m/s)^2 = 31.505 J

c)

We use the same formula as in a), but with m=28kg instead of 3 kg

v = (550 m/s ) (0.0250 kg/ 28 kg ) = 0.491 m/s

d)

Again, the same formula as b, but with m=28 and v=0.491 m/s

K = 3.375 J

e)

p_player = (110 kg)(8 m/s) = 880 kg m/s

p_ball = (0.41 kg)(25 m/s) = 10.25 kg m/s

I believe that the kinetic energy is more related to the problem than the momentum. The relation between these two quantities is:

K = p^2/(2m)

usiing this relation, we get:

K_player = 3520 J

K_ball =  128.125 J

Therefore the kinetic energy of the player is around 27 time larger than the kinetic energy of the ball, that being said, the pain of being tackled by that player is around 27 times greater that being hit by the ball!

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Where is most of the dark matter believed to be found in the galaxy?
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The barometer of a mountain hiker reads 930 mbars at the beginning of a hiking trip and 780 mbars at the end. Neglecting the eff
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We could use the change of pressure to calculate for the height climbed by the mountain hiker. The change of pressure is given by

p = rho * g * h, where p is the change of pressure, rho is the air density, g is the acceleration due to gravity, and h is the height.

Using the conversion 1 mbar = 100 Pa,

(930 - 780)(100) = (1.20)(9.80)h
15000 = 1.20*9.80*h

h = 1.28 km
6 0
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