(1/5)x + 8
This will find 20% of the wholesale cost and add the $8 markup, where 'x' is the wholesale cost
To solve this equation, first we have to use the distributive property to eliminate the parentheses on the left side of the equation.
If done correctly, your simplified equation should be
100,000 + 75,000x = 125,000
Next, we would subtract 100,000 from both sides, resulting in the equation
75,000x = 25,000
Finally, we would divide both sides of the equation by 75,000, resulting in your final answer of
x= 25,000/75,000
However, many mathematics teachers ask for fractional answers to be simplified. To simplify fractions, we first find the GCF of both numbers, and then divide both the numerator and the denominator by the GCF.
The GCF of 25,000 and 75,000 is 25,000.
So, in simplest form, your final answer is
x=1/3
Answer:
<h2>FALSE</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>tips and formulas:</h3>
order of PEMDAS
- parentheses
- exponent
- multiplication or
- division
- addition
- subtraction
<h3>let's solve:</h3><h2><u>L.</u><u>H.S</u><u>=</u></h2>
- <u></u>
- <u></u>
<h2><u>≠R.H.S</u></h2>
therefore
<h3>the equality is false</h3>
Given fraction:
-(6/-7)
Apply plus/minus rule:
-(-a)=a and -(a)=-a
So -(6/-7) = -6/-7= 6/7
Option D is correct.
Answer: (-6/-7)
a. percent of pig pregnancies that are longer than 106 days
Since we have a normal distribution here and the average number of days is 106, we can say that 50% of the pig pregnancies are longer than 106 days.
b. percent of pig pregnancies that are shorter than 111 days
To get the percentage, we will have to convert x = 111 days into a z-score first. The formula is:
where x = raw data, μ = population mean, and σ = population SD.
Since these 3 pieces of information are already given in the question, let's plug them into the equation above.
Therefore, 111 days is located 1 standard deviation to the right of the mean.
To find the percentage of pig pregnancies shorter than 111 days, we need to find the area covered to the left of 1 SD.
To find the area covered to the left of 1SD, we need to use the standard normal distribution table.
Based on the table, the area covered to the left of 1SD is 0.8413. Multiplying the area by 100, we get 84.13. Therefore, 84.13% of the pig pregnancies are shorter than 111 days.