It should be Quaternary (D)
I pretty sure it is the last one. Not completely sure though, hope this helps
Answer:
The oxidation state of sulfur, S, is +6, and the oxidation state of oxygen, O, is - 2:
Explanation:
Application of rules
1. <u>Ion SO₄²⁻</u>
In a neutral compound, the sum of the oxidation states of all the atoms that constitute the compound is equal to zero. In ions the sum of the oxidation states of the atoms is equal to the charge of the ion.
- In this case, the ion SO₄²⁻ has charge negative 2: - 2
<u>2. Oxygen</u>
With the exception of the peroxides, when oxygen is combined with other elements, it always has oxidation state - 2.
Hence, the total charge of the four atoms of oxygen in SO₄²⁻ is 4×(-2) = - 8.
<u>3. Sulfur</u>
Therefore, naming x the unknown oxidation state of S, you can set this equation:
- x + ( - 8) = - 2
- ⇒ x = - 2- ( - 8) = - 2 + 8 = + 6
Conclusion
- In SO₄²⁻, the oxidation state of sulfur, S, is +6, and the oxidation state of oxygen, O, is - 2.
Answer: Mixture
Explanation:
Element is a pure substance which is composed of atoms of similar elements.
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.
Mixture is a substance which has two or more components which do not combine chemically and do not have any fixed ratio in which they are present. Example: Air which conatins a mixture of 
, 
, 
and 
