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vitfil [10]
3 years ago
5

Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction betwe

en AA and BB, aA+bB⇌cC+dD aA+bB⇌cC+dD The dependence of the reaction rate on the concentration of each reactant is given by the equation called the rate law: rate=k[A]m[B]rate=k[A]m[B]n where kkk is a proportionality constant called the rate constant. The exponent mmm determines the reaction order with respect to AA, and nnn determines the reaction order with respect to BB. The overall reaction order equals the sum of the exponents (m+nm+n).
Chemistry
1 answer:
Studentka2010 [4]3 years ago
3 0

Explanation:

In the following reaction;

aA+bB⇌cC+dD

A and B are the reactants while C and D are the products.

a, b, c and d are regarded as coefficients.

The dependence of the reaction on the concentration of the reactants is given by the rate law.

This is given by;

rate= k [A]^m [B]^n

where

K = Rate constant. Constant for the reaction at that temperature.

m = order of reeaction with respect to A

n = order of reaction with repsect to B

Overall order of reaction is given by m + n

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In glycolysis, if glucose is labeled at the carbon 6 position (see page 1 for numbering of carbons in glucose) A) the carbon wit
Oliga [24]

Answer:

D) the carbon with the low-energy phosphate on it in 1,3 BPG is labeled.

Explanation:

Glycolysis has 2 phase (1) preparatory phase (2) pay-off phase.

<u>(1) Preparatory phase</u>

During preparatory phase glucose is converted into fructose-1,6-bisphosphate. Till this time the carbon numbering remains the same i.e. if we will label carbon at 6th position of glucose, its position will remian the same in fructose-1,6-bisphosphate that means the labeled carbon will still remain at 6th position.

When fructose-1,6-bisphosphate is further catalyzed with the help of enzyme aldolase it is cleaved into two 3 carbon intermediates which are glyceraldehyde 3-phosphate (GAP) and dihyroxyacetone  phosphate (DHAP).  In this conversion, the first three carbons of fructose-1,6-bisphosphate become carbons of DHAP while the last three carbons of fructose-1,6-bisphosphate will become carbons of GAP. It simply means that GAP will acquire the last carbon of fructose-1,6-bisphosphate which is labeled. Now the last carbon of GAP which has phosphate will be labeled.  

<u>(2) Pay-off phase</u>

During this phase, GAP is dehydrogenated into 1,3-bisphosphoglycerate (BPG) with the help of enzyme glyceraldehyde 3-phosphate dehydrogenase. This oxidation is coupled to phosphorylation of C1 of GAP and this is the reason why 1,3-bisphosphoglycerate has phosphates at 2 positions i.e. at position 1 in which phosphate is newly added and position 3rd which already had labeled carbon.

It is pertinent to mention here that<u> BPG has a mixed anhydride and the bond at C1 is a very high energy bond.</u> In the next step, this high energy bond is hydrolyzed into a carboxylic acid with the help of enzyme phosphoglycerate kinase and the final product is 3-phosphoglycerate. Hence, the carbon with low energy phosphate i.e. the carbon at 3rd position remains labeled.

3 0
3 years ago
lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is
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Answer:

The concentration is 0.036 mg/mL

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Jacob carelessly added only 40.0 mL (instead of the recommended 50.0 mL) of 1.1 M HCl to the 50.0 mL of 1.0 M NaOH. Explain the
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Answer:

Explanation:

mole of NaOH present = molarity x volume

                                     = 1.0 X 0.05 = 0.05 mole

<em>Recommended mole of HCl </em>= 1.1 x 0.05 = 0.055

<em>Mole of HCl carelessly added by Jacob </em>= 1.1 x 0.04 = 0.044

From the equation of reaction:

HCl + NaOH ----> NaCl + H2O

The ratio of mole of HCl to that of NaOH for a complete neutralization reaction is 1:1. However, the recommended mole of HCl (0.055 mole) is more than the mole of NaOH (0.05 mole). <u>Hence, the recommended endpoint of the reaction is supposed to be acidic.</u>

The mole of HCl added by Jacob (0.044) is short of the recommended amount (0.055) and also short of the amount required for a neutral endpoint (0.05). <u>This means that the endpoint will have an excess amount of NaOH and as such, basic instead of the desired acidic endpoint.</u>

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