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Inessa05 [86]
1 year ago
8

If one oscillation has 5. 8 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?

Physics
1 answer:
quester [9]1 year ago
7 0

The ratio of their amplitudes will be 2.41.

To find the answer, we have to know more about the simple harmonic motion.

<h3>How to find the ratio of their amplitudes?</h3>
  • It is given that,

                        E_1=5.8E_2\\m_1=m_2 \\\omega_1=\omega_2

  • We have the relation between these quantities and amplitudes as,

                        A=\sqrt\frac{2E}{k} \\k=m\omega^2

  • Here, for both the oscillation, k will be same.
  • Thus, the ratio of amplitude will be,

                      \frac{A_1}{A_2} =\sqrt{\frac{E_1}{E_2} } =\sqrt{\frac{5.8E_2}{E_2} } =2.41

Thus, we can conclude that, the ratio of their amplitudes will be 2.41.

Learn more about simple harmonic motion here:

brainly.com/question/22422926

#SPJ4

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Can someone help on this I'm really stuck
castortr0y [4]
Here, "Wavelength is same for both waves" it is the distance between two crests or two consecutive troughs, so, it is constant for both of them, you can easily figure it out.

In short, Your Answer would be "Wavelength"

Hope this helps!
5 0
3 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
Consider two less-than-desirable options.
Gemiola [76]

Answer:

The force would be the same in both cases - option C.

Explanation:

The change in momentum is known as an impulse. In the two cases under consideration, the change in momentum is the same, thus impulse for both cases is the same.

Impulse is the average force multiplied by time interval.

I = F(average)*ΔT. Where F(average) is the average force and ΔT is the time interval.

The average force in both cases is the same since the collision time is the same.

Thus option C is the correct answer.

7 0
3 years ago
A
Natasha_Volkova [10]

Answer:

i think it might be D or C

4 0
3 years ago
Automotive technology
viktelen [127]

lol what is this question

5 0
2 years ago
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