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AlekseyPX
3 years ago
13

The 1800 kg tractor exerts a force of 1.95 104 N backward on the pavement, and the system experiences forces resisting motion th

at total 2400 N. If the acceleration is 0.230 m/s2, what is the mass of the airplane in kilograms?
Physics
1 answer:
belka [17]3 years ago
7 0

Answer:72547.82 kg

Explanation:

Given

Mass of tractor is(M) 1800 kg

Force exerted (F)=1.95\times 10^4 N

Resisting Force(f_R)=2400 N

acceleration of system(a)=0.23 m/s^2

Let mass of airplane be m

so

F-f_r=(M+m)a

1.95\times 10^4-2400=(1800+m)\cdot 0.23

19500-2400=(1800+m)\cdot 0.23

1800+m=\frac{17,100}{0.23}

m=74347.82-1800=72547.82 kg

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Serga [27]

Answer:

B

Explanation:

Heat flows from hot to cold to lower the temperature of hot areas and increase temperature of cold areas. The end result is that the 2 areas have the same temperature, thus increasing entropy.

7 0
3 years ago
You drag a suitcase of mass 8.2 kg with a force of f at an angle 41.9 ◦ with respect to the horizontal along a surface with kine
DedPeter [7]

Answer:

35.6 N

Explanation:

We can consider only the forces acting along the horizontal direction to solve the problem.

There are two forces acting along the horizontal direction:

- The horizontal component of the pushing force, which is given by

F_x = F cos \theta

with \theta=41.9^{\circ}

- The frictional force, whose magnitude is

F_f = \mu mg

where \mu=0.33, m=8.2 kg and g=9.8 m/s^2.

The two forces have opposite directions (because the frictional force is always opposite to the motion), and their resultant must be zero, because the suitcase is moving with constant velocity (which means acceleration equals zero, so according to Newton's second law: F=ma, the net force is zero). So we can write:

F_x - F_f=0\\F_x = F_f\\F cos \theta = \mu mg\\F=\frac{\mu mg}{cos \theta}=\frac{(0.33)(8.2 kg)(9.8 m/s^2)}{cos(41.9^{\circ})}=35.6 N

8 0
3 years ago
What is the acceleration of a 59 kg object pushed with a force of 500 Newton's ?
Igoryamba

Answer:

a=500/50=10 m/s^2

Explanation:

f=m•a     a=f/m

a=500/50= 10 m/s^2

4 0
2 years ago
An engineer is designing a runway for a witch. Several brooms will use the runway and the engineer must design it so that it is
jonny [76]

Answer:

1170 m

Explanation:

Given:

a = 3.30 m/s²

v₀ = 0 m/s

v = 88.0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(88.0 m/s)² = (0 m/s)² + 2 (3.30 m/s²) (x - 0 m)

x = 1173.33 m

Rounded to 3 sig-figs, the runway must be at least 1170 meters long.

6 0
3 years ago
Solve the question that follows using the equation for the conversion of Celsius to Fahrenheit. F=95(C)+32 On February 9, 1934,
SVEN [57.7K]

Answer:

Buffalo, NY

Explanation:

Temperature in Buffalo, NY = -29°C

In order to compare the temperatures we need to convert them to the same scale.

F=\dfrac{9}{5}C+32\\\Rightarrow F=\dfrac{9}{5}\times -29+32\\\Rightarrow F=-20.2

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3 0
3 years ago
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