Base on your question where as a mass m is 15kg is pulled along a horizontal floor, with a coefficient of kinetic friction 0.06 and for a distance of D = 8.5 so the ask of the problem is to calculate the work done by tension before the bock. <span>Base on my calculation and through step by step procedure and with the guidance of the theories and by the use of formulas, I came up with an answer of 313 joules. </span>
This question is incomplete, the complete question is;
A weightlifter holds a 1,300 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the barbell. The chain has a total weight of 400 N. How much work (in J) is required to lift the barbell to a height of 2 m?
What is the average force (average with respect to height of the barbell from the ground) exerted by the weightlifter in the process?
Answer: Average force exerted by the weightlifter in the process = 1600N
Explanation:
To find Work done to lift a barbell and half of the hanging chain we say;
W₁ = ( 1300N + (1/2 × 400N)) × 1m
W₁ = (1300 + 200) Nm
W₁ = 1500J
now work done to lift the upper half of the chain we say:
W₂ = (1/2 × 400N) × (1/2 × 1m)
W₂ = 200N × 0.5m
W₂ = 100J
So total work done will be
W = W₁ + W₂
W = 1500J + 100J
W = 1600J
To find the average force exerted by the weight lifter, we say;
F = W/D
F = (1600 / 1m) N
F = 1600N
∴Average force = 1600N
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Answer:
c. hot material must be rising from the Sun's hotter interior
Explanation:
Granulation is the grainy appearance of the solar photosphere produced by the top of the convection cells in the sun.
The grainy appearance are produced by granules on the photosphere of the sun and granules are caused by convection currents of plasma within the sun's convection zone.
The interior of these granules are brighter (and thus hotter) than the exterior of the granules which are darker.
<u>So, the granulation pattern that astronomers have observed on the surface of the Sun tells us that hot material must be rising from the Sun's hotter interior.</u>