By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.
<h3>How to determine the speed?</h3>
First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:
S = ut + ½gt²
49 = 0(t) + ½ × 9.8 × t²
49 = 4.9t²
t² = 49/4.9
t = √10
t = 3.16 seconds.
Now, we can determine the speed at which he threw the second stone:
<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.
S = ut + ½gt²
49 = u(2.16) + ½ × 9.8 × 2.16²
49 = 2.16u + 22.86
2.16u = 49 - 22.86
u = 26.14/2.16
u = 12.10 m/s.
Read more on initial speed here: brainly.com/question/19365526
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Malleability is a useful property because it allows many products to be made in manufacturing.
Answer:
2123.55 $/hr
Explanation:
Given parameters are:
KV
L = 143 km
I = 500 A

So, we will find the voltage potential provided for the city as:
kV
kV
Then, we will find dissipated power because of the resistive loss on the transmission line as:
W
Since the charge of plant is not given for electric energy, let's assume it randomly as 
Then, we will find the price of energy transmitted to the city as:
$/hr
To calculate money per hour saved by increasing the electric potential of the power plant:
Finally,
$/hr
The amount of money saved per hour =
$/hr
Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.
The implication is that tilted sedimentary layers observed to day mist have been subjected to tectonic forces
Answer:
The force that you must exert on the balloon is 1.96 N
Explanation:
Given;
height of water, h = 4.00 cm = 4 x 10⁻² m
effective area, A = 50.0 cm² = 50 x 10⁻⁴ m²
density of water, ρ = 1 x 10³ kg/m³
Gauge pressure of the balloon is calculated as;
P = ρgh
where;
ρ is density of water
g is acceleration due to gravity
h is height of water
P = 1 x 10³ x 9.8 x 4 x 10⁻²
P = 392 N/m²
The force exerted on the balloon is calculated as;
F = PA
where;
P is pressure of the balloon
A is the effective area
F = 392 x 50 x 10⁻⁴
F = 1.96 N
Therefore, the force that you must exert on the balloon is 1.96 N