1 point

Having a good range of motion is super important because that is what allows you to ________________.

kotykmax [81]

A is the correct answer I think

6 0

2 years ago

What is the mass of a falling rock if it produces a force of 50 N?

Rasek [7]

×× $F=m \times a$ ×

50N is your force and the acceleration is -9.8m/s^2 due to gravity.

So, you just plug that in.

$50 N=m\times-9.8m/s^2\\
\frac{50}{-9.8}=m\\
m=-5.102$

BUT you know that mass cannot be negative, so you just disregard the negative sign and the mass of the rock is 5.102 grams.

8 0

3 years ago

The first law of thermodynamics states that ΔE= Q− W . Is this also a statement of the principle of conservation of energy? Yes,

ozzi

Answer:

Yes, the heat that flows into the system is used to change the internal energy of the gas and becomes work done by the piston.

Explanation:

First law of thermodynamics known as Law of Conservation of Energy, states that energy can neither be created nor destroyed; energy can only be transferred or changed from one form to another.

The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system. In equation form, the first law of thermodynamics.

This is the first law of thermodynamics

ΔE= Q− W

ΔE= change internal energy of the system.

Q= heat transfer into the system

And

W= work done by the system.

Rewriting the equation

ΔE= Q− W

Q=ΔE +W

Show that the heat flowing l into the system is transferred to the internal energy of the system and the work done by the piston

So the third option is correct

3 0

3 years ago

A uniform 6.84 m long horizontal beam that weighs 316 N is attached to a wall by a pin connection that allows the beam to rotate

denpristay [2]

Explanation:

Let us assume that moment about the pin and then setting it equal to zero as the rod is in equilibrium is as follows.

Moment = Force × Leverage

$-F_{T} Sin 55^{o} \times 6.84 m + 316 N \times \frac{6.84}{2} m + 608 N \times 6.84 m$

$-F_{T} \times 0.81915 \times 6.84 m + 316 N \times \frac{6.84}{2} m + 608 N \times 6.84 m$ = 0

$F_{T} = 935.11 N$

Therefore, we can conclude that the force ( $F_{T}$ ) in the cable by assuming that the origin of our coordinate system is at the rod’s center of mass is 935.11 N.

5 0

4 years ago

Astronauts on the first trip to Mars take along a pendulumthat has a period on earth of 1.50 {\rm s}. The period on Mars turns o

svetlana [45]

Answer:

3.7 m/s^2

Explanation:

The period of a simple pendulum is given by:

$T=2 \pi \sqrt{\frac{L}{g}}$

where L is the length of the pendulum and g is the free-fall acceleration on the planet.

Calling L the length of the pendulum, we know that:

$T_e = 2 \pi \sqrt{\frac{L}{g_e}}=1.50 s$ is the period of the pendulum on Earth, and $g_e = 9.8 m/s^2$ is the free-fall acceleration on Earth

$T_m = 2 \pi \sqrt{\frac{L}{g_m}}=2.45 s$ is the period of the pendulum on Mars, and $g_m = ?$ is the free-fall acceleration on Mars

Dividing the two expressions we get

$\frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}$

And re-arranging it we can find the value of the free-fall acceleration on Mars:

$g_m = g_e \frac{T_e^2}{T_m^2}=(9.8 m/s^2)\frac{(1.50 s)^2}{(2.45 s)^2}=3.7 m/s^2$

4 0

3 years ago